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3 years ago

Select the three equations that pass through the points (-4, -16) and (5,2).

Mathematics

2 answers:

dezoksy [38]3 years ago

5 0

Answer:

The equation of the line is $y-2 = 2(x - 5)$ , that passes through points $(-4, -16)\ and\ (5,2)$

Step-by-step explanation:

Given points are $(-4, -16)\ and\ (5,2)$

We need to write the equation of the line that passes through these points

First, we will find slope of this line

$m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{2-(-16)}{5-(-4)}\\\\m=\frac{2+16}{5+4}\\\\m=\frac{18}{9}=2$

So, our slope is $2$ . Now, we will plug the point $(5,2)$ in the equation below.

$(y-y_1)=m(x-x_1)\\y-2=2(x-5)\\$

So, the equation of the line is $y-2 = 2(x - 5)$ .

Studentka2010 [4]3 years ago

5 0

Answer:

It's B,C,D

Step-by-step explanation:

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What is the distance between the points (4, 6) and (5, 3)? Write the answer in simplest radical form.

frez [133]

Answer:

$\sqrt{10} \: \: units$

Step-by-step explanation:

$\sqrt{(6 - 3)^{2 } + (4 - 5)^{2} }$

$\sqrt{9 + 1}$

$\sqrt{10}$

= 3.16 units

7 0

3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

2 years ago

The square of a whole number 'n' lies between 80 and 150. Find all possible values for 'n'.

pychu [463]

The square of a whole number n lies between 80 and 150, so n lies between √80 and √150.

$\sqrt{80} \approx 8.9 \\
\sqrt{150} \approx 12.2$

n is a whole number and lies between 8.9 and 12.2, so n can be 9, 10, 11, or 12.

The possible values for n are 9, 10, 11, and 12.

5 0

4 years ago

For every arm a person has, they have a leg. Which ratio represents this situation?

Irina-Kira [14]

A: 1:1 unless they want you to count both arms then it would be B: 2:2

3 0

3 years ago

Read 2 more answers

Jason wanted to buy postcards for his cousin. The price was 2 cards for $1. He had some change in his pocket. What combination o

Zina [86]

Answer:

2 dimes, 1 nickel and 3 quarters.

Step-by-step explanation:

The price of 2 postcards is $1. Any combination of coins that adds to $1 will work here. Remember, a penny is worth 0.01, a nickel is worth 0.05, a dime is worth 0.10, and a quarter is worth 0.25.

Adding 2 dimes, 1 nickel, and 3 quarters would be 2(0.10)+1(0.05)+3(0.25)=1.

8 0

3 years ago