8th grader here, what do you need help with?
2x² - 128
2(x² - 64), but (x² - 64) = x² - 8² (difference of 2 squares),[a²-b²=(a-b)(a+b)]
2(x² - 64) = 2(x² - 8²) = 2(x-8)(x+8)
Answer:
789
Step-by-step explanation:
Answer:
you are going to have to look from left to right and see if it is above or below
1
Move everything to the left by subtracting 25 from both sides:

Both terms are squares:
is the square of
, while 25 is the square of 5. So, we can apply the factoring

To factor the expression as

A multiplication is zero if and only if one of the factors is zero, so we have

2
The discriminant of the quadratic expression
is defined as

So, you have

3
Similarly, we have
