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Anestetic [448]
3 years ago
12

Which of the expressions are equivalent to angle z?​

Mathematics
1 answer:
san4es73 [151]3 years ago
8 0

heskjjehrjefrkhbjhgfrkjfrfvbnrjgjrnnqojdhf

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Samantha sells pre-owned automobiles for Fast Track Motors. She receives a monthly salary of $750. Samantha also receives a comm
RUDIKE [14]
0.015*202455 =  3,036.825
3,036.825+750 = 3,786.83

$3,786.83
6 0
3 years ago
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Whats the fraction form for 0.44
Amiraneli [1.4K]
The fraction form is 11/25
Hope this helps!!!!:)

8 0
3 years ago
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The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i
kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.


Recall the formula for the sum of consecutive positive integers,

\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2

Now,

1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224

numbers, and their sum is

\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of 1+9\times2=19.

So, the sum of the first 1234 terms in the sequence is 2419.

8 0
2 years ago
84052 in word from plz need help in my homework
SOVA2 [1]
<span>Eighty-four thousand, fifty-two</span>
5 0
3 years ago
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Write a polynomial of degree 3 whose only roots are x=2 and x=2/5. Is there another polynomial of degree 3 that has the same roo
TEA [102]
One such polynomial might be

(x-2)\left(x-\dfrac25\right)^2

Another with the same roots would be

(x-2)^2\left(x-\dfrac25\right)
7 0
3 years ago
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