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3 years ago

In the target above, how would you classify the "hits"? (Note: an accurate "hit" is a bull's-eye.)

Chemistry

2 answers:

Naddik [55]3 years ago

7 0

Explanation:

Since no diagram is given, we can solve this problem by carefully going through this explanation.

Precision and accuracy are terms used to express the confidence and reliability of some given measurement of experiment. Here it is the dart game we are referencing.

Precision is the ability to reproduce a particular set of results. It is the repeatability of a single result.
Accuracy is the nearness of a measurement to the the true value.

In the dart game, if we hit the bull eye or we are close to hitting it, we can assume that our throw is accurate.

If we throw several darts at the same place at the different times then our throw is precise.

If we multiple darts that all hits the bull's eye then our throw is accurate and precise.

If we have multiple throws scattered all over, then they are neither precise nor accurate.

learn more:

Accuracy brainly.com/question/5145821

#learnwithBrainly

Effectus [21]3 years ago

5 0

Answer:

Explanation:

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Jimmy's science textbook reflects blue light. What color is the book?

Dmitry [639]

I’m not sure but i think blue

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3 years ago

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Write the reaction equation and equilibrium equation for dopamine

elena-s [515]

Answer:

The see explanation

Explanation:

In this case, we have an "amine" group in the dopamine structure. So, the dopamine will act as a "base". A base is a substance that has the ability to accept hydrogens, therefore, the $NH_2$ will take hydrogen from the water molecule. Additionally, the water will produce the $OH^-$ ion and the $NH_2$ will be converted into $NH^+_3$ .

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3 years ago

Draw the correct structural formula for the following compounds:

Anvisha [2.4K]

Answer:

Explanation:

a) H3C-CH=CH-CH2-CH3

b) CH3 CH3

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CH3-C- CH- CH2- CH-CH3

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C2H5 C2H5

c) C2H5

CH3-C=CH-CH-CH2-CH-CH3

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CH3 CH3

6 0

4 years ago

will give brainliest!! please help ! .. Calculate the total pressure of the mixture in atmospheres ( atm ).

nordsb [41]

Answer:

13.94 atm

Explanation:

From the question given above, the following data were obtained:

Pressure of H₂ = 2 atm

Pressure of NH₃ = 303 KPa

Pressure of CO₂ = 3000 mmHg

Pressure of N₂ = 3800 torr

Total pressure (Pₜ) in atm =?

Next, we shall convert 303 KPa, 3000 mmHg and 3800 torr to atm.

This can be obtained as follow:

Converting 303 KPa to atm

101.325 KPa = 1 atm

Therefore,

303 KPa = 303 KPa × 1 atm / 101.325 KPa

303 KPa = 2.99 atm

Thus, 303 KPa is equivalent to 2.99 atm.

Converting 3000 mmHg to atm

760 mmHg = 1 atm

Therefore,

3000 mmHg = 3000 mmHg × 1 atm / 760 mmHg

3000 mmHg = 3.95 atm

Thus, 3000 mmHg is equivalent to 3.95 atm

Converting 3800 torr to atm

760 torr = 1 atm

Therefore,

3800 torr = 3800 torr × 1 atm / 760 torr

3800 torr = 5 atm

Thus, 3800 torr is equivalent to 5 atm.

Finally, we shall determine the total pressure of the mixture as follow:

Pressure of H₂ (P₁) = 2 atm

Pressure of NH₃ (P₂) = 2.99 atm

Pressure of CO₂ (P₃) = 3.95 atm

Pressure of N₂ (P₄) = 5 atm

Total pressure (Pₜ) in atm =?

Pₜ = P₁ + P₂ + P₃ + P₄

Pₜ = 2 + 2.99 + 3.95 + 5

Pₜ = 13.94 atm

Therefore, the total pressure of the mixture is 13.94 atm

4 0

3 years ago

A 10.8ml sample of sulfuric acid titrated with 80.0 ml of 0.200 m mg solution. What is the concentration of the sample given the

IRISSAK [1]

Answer:

1.48 M

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

Mg + H2SO4 —> MgSO4 + H2

Step 2:

Determination of the number of mole of Mg in 80.0 mL of 0.200 M Mg solution. This is illustrated below:

Molarity of Mg = 0.200 M

Volume of solution = 80 mL = 80/1000 = 0.08L

Mole of Mg =?

Molarity = mole /Volume

0.2 = mole /0.08

Mole = 0.2 x 0.08

Mole of Mg = 0.016 mole.

Step 3:

Determination of the number of mole of H2SO4 that reacted. This is illustrated below:

Mg + H2SO4 —> MgSO4 + H2

From the balanced equation above,

1 mole of Mg reacted with 1 mole of H2SO4.

Therefore, 0.016 mole of Mg will also react with 0.016 mole of H2SO4.

Step 4:

Determination of the concentration of the acid.

Mole of H2SO4 = 0.016 mole.

Volume of acid solution = 10.8 mL = 10.8/1000 = 0.0108 L

Molarity =?

Molarity = mole /Volume

Molarity = 0.016/0.0108

Molarity of the acid = 1.48 M

Therefore, the concentration of acid is 1.48 M

8 0

4 years ago