Answer:
34.44 g.
Explanation:
- The balanced equation for the reaction is:
<em>Fe + S → FeS,</em>
<em></em>
<em>It is clear that 1.0 mol of Fe reacts with 1.0 mol of S to produce 1.0 mol FeS.</em>
<em />
- We need to calculate the no. of moles of 60 grams of iron and 90 grams of iron sulfide:
no. of moles of Fe = mass/atomic mass = (60.0 g)/(55.845 g/mol) = <em>1.074 mol.</em>
<em>no. of moles of FeS = mass/molar mass</em> = (90.0 g)/(87.91 g/mol) = <em>1.024 mol.</em>
<u><em>∵ Fe reacts with S with (1: 1) molar ratio.</em></u>
∴ The no. of moles of S needed to react with Fe is 1.074 mol.
<em>∴ The no. of grams of S needed = no. of moles x molar mass </em>= (1.074 mol)(32.065 g/mol) = <em>34.44 g.</em>
I believe it is Good
Please give me Brainliest
Answer:
copper has 2+ ions in a sample of copper
<h3>
Answer:</h3>
14 milliliters
<h3>
Explanation:</h3>
We are given;
Prepared solution;
- Volume of solution as 0.350 L
- Molarity as 0.40 M
We are required to determine the initial volume of HNO₃
- We are going to use the dilution formula;
- The dilution formula is;
M₁V₁ = M₂V₂
Rearranging the formula;
V₁ = M₂V₂ ÷ M₁
=(0.40 M × 0.350 L) ÷ 10.0 M
= 0.014 L
But, 1 L = 1000 mL
Therefore,
Volume = 14 mL
Thus, the volume of 10.0 M HNO₃ is 14 mL
Answer:
b
Explanation:
I used my passion and skill for learning to do a quick google search :P
