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Oksi-84 [34.3K]
3 years ago
8

Many large and small rocks are found under glaciers. Explain how these rocks are both weathered and eroded.

Chemistry
2 answers:
topjm [15]3 years ago
8 0
These rocks eroded by the water slowly taking tiny pieces of the rock away and moving them somewhere else
Mumz [18]3 years ago
7 0

Answer:

The ice and water hit the small rocks and take apart the sediments from it

Explanation:

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A syringe containing 1.63 mL of oxygen gas is cooled from 91.0 ∘C to 0.9 ∘C. What is the final volume Vf of oxygen gas? (Assume
Archy [21]

Answer:

Vf = 1.22 mL

Explanation:

If we assume that the pressure is constant and the number of moles does not change, we can say that the volume of the gas is modified in a directly ratio, to the Absolute Temperature.

Let's convert the values:

91°C + 273 = 364K

0.9°C + 273 = 273.9K

Volume decreases if the temperature is decreases

Volume increases if the T° increases

V₁ / T₁  = V₂ / T₂ → 1.63mL /364K = V₂ / 273.9K

V₂ = (1.63mL /364K) . 273.9K → 1.22 mL

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4 years ago
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Question 5 (5 points)
Dima020 [189]

Answer:

They Are all O's/oberavtions, because inference is using facts and reasoning, which is not the case here.

Explanation:

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3 years ago
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In process in which An animal's cells use oxygen and digested food molecules to release the energy in food is called
mamaluj [8]
In process in which An animal's cells use oxygen and digested food molecules to release the energy in food is called

cellular respiration
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3 years ago
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1.) What are the two broad categories that elements can be divided into?
hoa [83]

Answer:

1) Metals and nonmentals

2) Elements: Oxygen (O_{2} \\) , Nitrogen (N_{2}

3) Compounds: Carbon Dioxide CO_{2}, Methane CH_{4}, Nitrogen DioxideNO_{2}

Explanation:

5 0
3 years ago
Gaseous methane CH4 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is the t
Murrr4er [49]

Answer:

50.8 g

Explanation:

Equation of reaction.

CH_4 + 2O_2 \to CO_2 + 2H_2O

From the given information, the number of moles of methane = mass/ molar mass

= 15.4 g /  16.04 g/mol

= 0.960 mol

number of moles of oxygen gas = 90.3 g / 32 g/ mol

= 2.82 mol

Since 1 mol of methane requires 2 moles of oxygen

Then 0.960 mol of methane will require = 0.960 mol × 2 = 1.92 mol of oxygen gas

Thus, methane serves as a limiting reagent.

2.82 mol oxygen gas will result in 2.82 moles of water

So, the theoretical yield of water = moles × molar mass

= 2.82 mol × 18.01528 g/mol

= 50.8 g

8 0
3 years ago
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