Here is an example I did of the problem hope it helps let me know if you need anything else~!
~<span>Cecildoesscience </span>
![\sf{14(\sqrt[3]{x}) }](https://tex.z-dn.net/?f=%5Csf%7B14%28%5Csqrt%5B3%5D%7Bx%7D%29%20%7D)
Step-by-step explanation:
![5(\sqrt[3]{x})+9(\sqrt[3]{x})\\\\(5+9)(\sqrt[3]{x})\\\\14(\sqrt[3]{x})](https://tex.z-dn.net/?f=5%28%5Csqrt%5B3%5D%7Bx%7D%29%2B9%28%5Csqrt%5B3%5D%7Bx%7D%29%5C%5C%5C%5C%285%2B9%29%28%5Csqrt%5B3%5D%7Bx%7D%29%5C%5C%5C%5C14%28%5Csqrt%5B3%5D%7Bx%7D%29)
This is vague. Any dimensions that make a triangle can make more than one, just draw another right next to it. What's really being asked is which dimensions can make more than one non-congruent triangle.
<span>A. Three angles measuring 75°,45°, and 60°.
That's three angles, and 75+45+60 = 180, so it's a legit triangle. The angles don't determine the sides, so we have whole family of similar triangles with these dimensions. TRUE
<span>B. 3 sides measuring 7, 10, 12?
</span>Three sides determine the triangles size and shape uniquely; FALSE
<em>C. Three angles measuring 40</em></span><span><em>°</em></span><em>, 50°</em><span><em>, and 60°? </em>
40+50+60=150, no such triangle exists. FALSE
<em>D. 3 sides measuring 3,4,and 5</em>
Again, three sides uniquely determine a triangle's size and shape; FALSE
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