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kicyunya [14]
3 years ago
5

Which theorem can you use to prove that AAEB is congruent to ACED?

Mathematics
2 answers:
sleet_krkn [62]3 years ago
6 0
I don’t no sorry bye
S_A_V [24]3 years ago
4 0
It think you can do SSS or SAS
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If x represents a number, then write an expression for a number that is three more than the number,
jekas [21]
The answer is 828282827337829245902637
7 0
3 years ago
Pls help!!!!
iris [78.8K]

from 300 to 250 is well, just a change of 50 units.

if we take the 300 as the 100%, what is 50 off of it as percentage?

\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 300&100\\ 50&x \end{array}\implies \cfrac{300}{50}=\cfrac{100}{x}\implies 6=\cfrac{100}{x}\implies 6x=100 \\\\\\ x=\cfrac{100}{6}\implies x=\cfrac{50}{3}\implies x=16.666666\overline{6}\implies \stackrel{\textit{rounded up}}{x = 16.7}

3 0
3 years ago
Read 2 more answers
(1 point) The systolic blood pressure (given in millimeters) of males has an approximately normal distribution with a mean of 12
garik1379 [7]

Answer:

a) Z = -2.7

b) Z = 2.3

c) Kyle's systolic blood pressure is 1.75 standard deviations above the average systolic blood pressure for men.

d) X = 144.5

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 127, \sigma = 10

(a) 100 millimeters z-score =

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 127}{10}

Z = -2.7

(b) 150 millimeters z-score =

Z = \frac{X - \mu}{\sigma}

Z = \frac{150 - 127}{10}

Z = 2.3

(c) Kyle's doctor told him that the z-score for his systolic blood pressure is 1.75. Which of the following is the best interpretation of his score?

1.75 standard deviations above the mean systolic blood pressure of males.

The problem does not talk about age.

So the answer is:

Kyle's systolic blood pressure is 1.75 standard deviations above the average systolic blood pressure for men.

d) Calculate Kyle's blood pressure

This is X when Z = 1.75. So

Z = \frac{X - \mu}{\sigma}

1.75 = \frac{X - 127}{10}

X - 127 = 1.75*10

X = 144.5

7 0
4 years ago
Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)<br>​
Ksju [112]

Step-by-step explanation:

(\sec A - \csc A)(1 + \cot A + \tan A)

=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)

=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)

=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)

=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)

=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}

=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}

=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}

=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}

=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)

=\sec^2A\csc A -  \csc^2A\sec A

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5x-8(3y+13)-1 what's the expression
Tanya [424]
Did u try looking it up?
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