Answer:
There are 70 sheep in the farm.
Step-by-step explanation:
Consider the provided information.
Let c represents the cows, s represents the sheep and p represents the pigs.
The number of cows and the number of sheep are in the ratio 6:5.
The number of sheep and the number of pigs are in the ratio 2:1.
The total number is 189.
Substitute the value of c and p in above.
Hence, there are 70 sheep in the farm.
The partial fraction decomposition is
The fraction is given as:
Split the fraction as follows:
Take the LCM
Cancel the common factors
8x + 19 = Ax - A + Bx + 8B
By comparison, we have:
Ax + Bx = 8x
-A + 8B = 19
This gives
A + B = 8
-A + 8B = 19
Add both equations
9B = 27
Divide by 9
B = 3
Substitute B = 3 in A + B = 8
A + 3 = 8
Solve for A
A = 5
So, we have:
Hence, the partial fraction decomposition is
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A projectile is an object <u>launched</u> into space, and moving under the <em>influence</em> of <u>gravity</u> and <u>momentum</u>. The <em>stone</em> here is an example. Thus, the <em>time</em> taken for the stone to reach the ground is 10 seconds.
On <em>launching</em> of the stone into <u>space</u>, it behaves as a <u>projectile</u>. Thus moving under the <em>influence</em> of gravity and its momentum. Its <u>momentum</u> is the <em>product</em> of its <u>mass </u>and <u>velocity</u>.
The height h, is given as:
h = 16 + 32t + 240
Differentiating the expression with respect to t, we have;
32t + 32 = 0
t = -1 seconds
Substitute the value of time, t, in the equation for the height;
h = 16 - 32 + 240
= 224
h = 224 m
Total height, S = 240 + 224
= 464
S = 464 m
The total height covered by the stone is 464 m.
From the second equation of <em>free fall</em>,
S = Ut + g
S = g
464 = *9.8*
=
= 94.694
t =
= 9.7311
t ≅ 10 seconds
The <em>time taken</em> for the stone to hit the ground is 10 seconds.
Thus option A is the required answer.
Answer:
Step-by-step explanation:
I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):
** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.
** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.
** Due east has an angle measure of 0 degrees
Now let's begin.
We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:
so
so
and we need to add those results together. Due to the rules for adding significant digits properly, the answer is
(and remember I am counting that as 3 sig fig's even though it's only 1).
Now for the y components:
so
(which I'm counting as 2 sig fig's)
so
and we need to add those results together.
Now for the resultant magnitude:
and that gives us a final magnitude of
m
Now for the angle:
Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so
The girl is 206 meters from her starting point at an angle of 14 degrees