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4 years ago

U

Mathematics

1 answer:

julia-pushkina [17]4 years ago

3 0

Answer:

Step-by-step explanation:

The French Revolution, if anything, was the most momentous event of the 18th century, even grander than the American Revolution. Its design, the causes, the results, and the ideology are so hard to perfectly pin down, so much so that there are many, many different schools of thought on it. There is classic historiography (Aulard, Lefebrves, Mathiez, etc.). There are the liberal

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What is the LCDof two numbers if one number is a multiple of the other give an example

mylen [45]

What's the choices to the question

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3 years ago

Jana can spend, at most, $200 on school clothes.

Soloha48 [4]

Answer:

x <= 200

Step-by-step explanation:

Your answer choices are unclear so I cannot specify a letter. The answer is

x<=200.

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3 years ago

Read 2 more answers

17. Lyndsey is at basketball practice preparing to shoot free throws. The probability of Lyndsay

hram777 [196]

Answer:

Probabilty that Lindsay makes her first free throw on the third shot $=0.027$

Step-by-step explanation:

Given:

Probability of Lindsay making a free throw $=82\% =\frac{82}{100}=0.82$

To find probability of Lindsay making her first free throw in the third shot.

If Lindsay makes her first free throw on the third shot then its means the first two shots must have been unsuccessful ones.

Probability of Lindsay not making a free throw $1-0.82=0.18$

First shot ⇒ $P(unsuccessful)=0.18$

Second shot ⇒ $P(unsuccessful)=0.18$

Third shot ⇒ $P(successful)=0.82$

∴ Probabilty that Lindsay makes her first free throw on the third shot $=0.18\times0.18\times0.82=0.027$

5 0

4 years ago

A package of 88 batteries costs $ 4 . 724.72 .

Vikki [24]

SOLUTION:

8 batteries = $4.72

8 ÷ 8 = 4.72 ÷ 8

1 battery = $0.59

Therefore, the cost of per battery is $0.59.
(sorry if this isn’t the correct answer)

5 0

3 years ago

Read 2 more answers

Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su

Alja [10]

Answer:

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

Step by step explanation:

$\frac{ {(4 {n}^{4} {q}^{5})}^{2} {(8 {n}^{4} q)}^{-2} }{ {(- 3 {nq}^{9})}^{ - 1} {(4 {n}^{3} {q}^{9}) }^{3} }$

first we will change the terms with negative superscrips to the other side of the fraction

$\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }$

then we will distribute the superscripts

$\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2} {q}^{2} }$

$\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8} {q}^{2} }$

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

${4}^{2 - 3} {q}^{10 + 9 - 2 - 27} {n}^{8 + 1 - 8 - 9} {8}^{ - 2} { (- 3)}^{1}$

${4}^{ - 1} {q}^{ - 10} {n}^{ - 8} {8}^{ - 2} { (- 3)}^{1}$

then we will change again the terms with negative superscrips to the other side of the fraction

$\frac{ - 3}{ 4 \times {8}^{2} {q}^{10} {n}^{8} }$

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

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3 years ago