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lora16 [44]
3 years ago
10

Liam and Pam with ropes

Mathematics
1 answer:
Sedaia [141]3 years ago
8 0
Are Angles because they deserve so such and are well influenced personnel
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2x+4 is the length of one side
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Given the equation below, what is the value of 3 + 6(79 – s)?<br> 7= -s+ 82
ss7ja [257]

Answer:

1 expression) 477 - 6s

2 equation) s = 75

Step-by-step explanation:

Also, the first expression is simplified

4 0
3 years ago
Mr Thompson please help with my new HW
sesenic [268]

Answers:

  1. C) x = plus/minus 11
  2. B) No real solutions
  3. C) Two solutions
  4. A) One solution
  5. The value <u>  18  </u> goes in the first blank. The value <u>  17  </u> goes in the second blank.

========================================================

Explanations:

  1. Note how (11)^2 = (11)*(11) = 121 and also (-11)^2 = (-11)*(-11) = 121. The two negatives multiply to a positive. So that's why the solution is x = plus/minus 11. The plus minus breaks down into the two equations x = 11 or x = -11.
  2. There are no real solutions here because the left hand side can never be negative, no matter what real number you pick for x. As mentioned in problem 1, squaring -11 leads to a positive number 121. The same idea applies here as well.
  3. The two solutions are x = 0 and x = -2. We set each factor equal to zero through the zero product property. Then we solve each equation for x. The x+2 = 0 leads to x = -2.
  4. We use the zero product property here as well. We have a repeated factor, so we're only solving one equation and that is x-3 = 0 which leads to x = 3. The only root is x = 3.
  5. Apply the FOIL rule on (x+1)(x+17) to end up with x^2+17x+1x+17 which simplifies fully to x^2+18x+17. The middle x coefficient is 18, while the constant term is 17.
3 0
3 years ago
Below is the five-number summary for 144 hikers who recently completed the John Muir Trail (JMT). The variable is the amount of
bearhunter [10]

Answer:

The IQR is given by:

IQR = Q_3 -Q_1 = 28-18= 10

If we want to find any possible outliers we can use the following formulas for the limits:

Lower= Q_1 - 1.5 IQR

Upper= Q_3 + 1.5 IQR

And if we find the lower limt we got:

Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3

Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43

So then the left boundary for this case would be 3 days

Step-by-step explanation:

For this case we have the following 5 number summary from the data of 144 values:

Minimum: 9 days

Q1: 18 days

Median: 21 days

Q3: 28 days

Maximum: 56 days

The IQR is given by:

IQR = Q_3 -Q_1 = 28-18= 10

If we want to find any possible outliers we can use the following formulas for the limits:

Lower= Q_1 - 1.5 IQR

Upper= Q_3 + 1.5 IQR

And if we find the lower limt we got:

Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3

Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43

So then the left boundary for this case would be 3 days

6 0
3 years ago
125 invitations to 75 Invitations ( Round To The Nearest Tenth Of A Percent If Necessary )
aleksklad [387]
I think the answer to this is .6 or 1.7

8 0
3 years ago
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