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bija089 [108]
3 years ago
8

A FEW MATH QUESTIONS ! PLEASE EXPLAIN ANSWERS ! (:

Mathematics
2 answers:
aliina [53]3 years ago
6 0

Answer:

C

C

C

D

Step-by-step explanation:

One

LA (Lateral Area) = 2.5 * BA (Base Area)

LA = 2.5 * 20

LA = 50 in^2

But the surface area = Lateral Area + Base

LA = 50

Base = 20

Total Surface Area = 70

Answer C

Two

The hypotenuse of the triangle is sqrt(a^2 + b^2)

a = 12

b = 16

c = ?

c =sqrt(12^2 + 16^2)

c = sqrt(144 + 256)

c = sqrt(400)

c  = 20

Volume of rectangular Prism= L*W*H

L = 20

W = 12

H = 16

V =  20 * 12 * 16

V = 3840

C <<<<< answer

Three

V_cone = 1/3 B * H

3 * V_cone = BH

V_cylinder= B * H          Equate equals to equals.

V_cylinder =3 * Cone

The cylinder has 3 times the volume of the cone.

V_cylinder = 3 * 12ft^3

V_cylinder = 36 ft^3

Answer C

Four

B = 1/2 * b * h of the triangle

Volume of pyramid = 1/3 * 1/2 * b * h * H where H is the height of the Pyramid.

Volume of Pyramid = 1/6 * b*h * H   Now b*h*H are each doubled.

Volume of Pyramid = 1/6 * (2*b)(2*h)(2*H)

Volume of New Pyramid = 1/6 * 8 (b * h  * H)

The volume has increased by a factor of 8.

If the smaller pyramid was 9  then the new larger one is 8*9 = 72

D <<<< answer

7nadin3 [17]3 years ago
3 0

answers

1) 70

2) 3,840

3) 24

4) 72


<u>Explanation</u>

Q1

The surface area of a cone is given by;

S.A = 2Πrl + Πr²

Where r is the radius of the base and l is the lateral height.

Πr² = area of the base = 20 in²

2Πrl = Area of the lateral surface

         = 2.5 × 20

          = 50

Area of the cone = 50 + 20

                            = 70 in²

Q2

The sides of the Pythagorean triangle with legs of 12 and 16.

The 3rd side will be;

c = √(12² + 16²)

  = √400 = 20

Volume = 12 × 16 × 20

              = 3,840

Q3

The volume of a cone is given by;

volume = 1/3 Π r² h

This shows that the volume of a cone is a third the volume of the cylinder.

∴ Volume of the cylinder = 12 × 3

                                            = 24 ft³

Q4

The volume of any regular figure is;

Volume = base area × height

When the dimensions area usually 3. Let these dimensions be x, y and z.

∴ volume  = x × y × z = 9

  Doubling the dimensions;

Volume = 2x × 2y × 2z = 2 × 2 × 2 × 9

             = 8 × xyz = 8 × 9

             = 72 ft²



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Consider the initial value function y given by
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Answer:

y(s) = \frac{5s-53}{s^{2} - 10s  + 26}

we will compare the denominator to the form (s-a)^{2} +\beta ^{2}

s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}

comparing coefficients of terms in s

s^{2} : 1

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constant: a^{2}+\beta ^{2} = 26

               (\frac{1}{5} )^{2} + \beta ^{2} = 26\\\\\beta^{2} = 26 - \frac{1}{10} \\\\\beta =\sqrt{26 - \frac{1}{10}} =5.09

hence the first answers are:

a = 1/5 = 0.2

β = 5.09

Given that y(s) = A(s-a)+B((s-a)^{2} +\beta ^{2} )

we insert the values of a and β

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to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A

5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)

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B = -52/26 = -2

to get A lets substitute s=0.4

5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)

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0.2A = -51 + 52.08

A = -1.08/0.2 = 5.4

<em>the constants are</em>

<em>a = 0.2</em>

<em>β = 5.09</em>

<em>A  = 5.4</em>

<em>B = -2</em>

<em></em>

Step-by-step explanation:

  1. since the denominator has a complex root we compare with the standard form s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}
  2. Expand and compare coefficients to obtain the values of a and <em>β </em>as shown above
  3. substitute the values gotten into the function
  4. Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
  5. after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above

Thanks...

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