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MAVERICK [17]
3 years ago
13

si la suma de dos veces el primer numero entero y tres veces el segundo entero es 48, cuales son los enteros?

Mathematics
1 answer:
Vlad1618 [11]3 years ago
5 0

Hello from MrBillDoesMath!

Answer:

The integers cannot be uniquely determined


Discussion:

Let the first integer be "f" and the second integer "s".

From the Question

2f + 3s = 48


The values f and s can NOT be uniquely determined.

For example, f = 24, s = 0 is one solution.

f = 0, s = 16 is another....

f = 12, s = 8 is yet another!


See the problem?  The Question needs to be clarified



Thank you,

MrB

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for\ x=0\to y=12\sqrt{4\cdot0}+10=12\sqrt0+10=10\\for\ x=1\to y=12\sqrt{4\cdot1}+10=12\sqrt4+10=12\cdot2+10=34\\for\ x=4\to y=12\sqrt{4\cdot4}+10=12\sqrt{16}+10=12\cdot4+10=58\\for\ x=6\to y=12\sqrt{4\cdot6}+10=12\cdot2\sqrt6+10=24\sqrt6+10\approx69\\for\ x=10\to y=12\sqrt{4\cdot10}+10=12\cdot2\sqrt{10}+10=24\sqrt{10}+10\approx86\\for\ x=12\to y=12\sqrt{4\cdot12}+10=12\cdot4\sqrt3+10=48\sqrt3+10\approx93

\underline{x|\ 0|\ 1\ |\ 4|\ 6\ |10|12|}\\y|10|34|58|69|86|93|

\text{The graph in attachment}

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