216 =6^3
1,296 = 6^4
7,776 = 6^5
x = 6^f(x)
log x = log 6^f(x) = f(x)log 6
f(x) = log x / log 6 =
Answer:
Danny
Step-by-step explanation:
danny has a better offer
Answer:
113 feet
Step-by-step explanation:
I will assume you meant h = -4.9t^2 + 135; "t2" is incorrect.
To answer this question, to find the height of the ball after 2.1 seconds, substitute 2.1 for t in the above equation:
h(2.1) = -4.9(2.1)^2 + 135. This becomes -21.6 + 135, or 113.4.
The closest result to the height of the ball after 2.1 seconds is 113 feet.
You have to subtract do it will come out as 175. learn how to subtract big digets and then you will know how to do it tell your teacher that you need help with that.
To answer this question, you should set up and equation before doing anything else. So for this question you 're going to set up two equations.
The first equation is 2x+5y=33
The second equation is 8x+3y=30
Once you do that you have to solve for either X or Y by canceling out the other one. In this problem figuring out the Y is easier because you can cancel the X's more easily than the Y. To cancel a variable, they have to add up to 0.
So to cancel the X you multiply the equation 2x+5y=33 by -4.
That gives you -8x-20y= -132
Then you set up the two equations and add them together.
(-8x-20y= -132) + (8x+3y=30)
That gives you -17y = -102
So then you solve for Y by dividing by -17. You find out that Y is equal to 6. Then you plug the 6 back into the ORIGINAL equations and solve for X, which turns out to be 1.5
Hope this helped and if you get confused or have questions please ask :)
