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Evgen [1.6K]
3 years ago
5

A tungsten resistance thermometer with a range of –270 to þ1100C has a quoted inaccuracy of1.5% of full-scale reading. What is t

he likely measurement error when it is reading a temperature of 950C?
Mathematics
1 answer:
lara31 [8.8K]3 years ago
6 0

Answer:

idk

Step-by-step explanation:

fyjndkuych

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Sugar: x pounds
flour: 2x + 5 pounds
2x + 3(2x + 5) = 40
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8x = 25
x = 3.125
-> a sack of flour is 3.125 + 5 = 8.125 pounds
I hope it‘s coorect
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Simplify 3(x+2)-9x+5
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It would be...
-6x+11
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What is the answer to number 1 and why
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I say B, I had to google it to make sure, but there are 3 phases in interphase. Interphase occurs before mitosis. The third phase in interphase is the DNA being copied.
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3 years ago
A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature
Westkost [7]

Answer:

(a) The value of <em>k</em> is \frac{1}{15}.

(b) The probability that at most three forms are required is 0.40.

(c) The probability that between two and four forms (inclusive) are required is 0.60.

(d)  P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 is not the pmf of <em>y</em>.

Step-by-step explanation:

The random variable <em>Y</em> is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of <em>k</em>.

\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}

Thus, the value of <em>k</em> is \frac{1}{15}.

(b)

Compute the value of P (Y ≤ 3) as follows:

P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\   =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 to be the pmf of Y it has to satisfy the conditions:

  1. P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\
  2. \sum P(y)=1

<u>Check condition 1:</u>

y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0

Condition 1 is fulfilled.

<u>Check condition 2:</u>

\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1

Condition 2 is not satisfied.

Thus, P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 is not the pmf of <em>y</em>.

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Step-by-step explanation:

Since , internal sum of angle of triangle is 180°

So,

66 + x +49 + x+83 = 180

or, 198 + 2x = 180

or, 2x = 180 -198

or, 2x = -18

hence, x = - 9

Now angle A = x + 49

= (-9) + 49

= 40

<u>Hence </u><u>measure</u><u> </u><u>of </u><u>angle </u><u>A </u><u>is </u><u>4</u><u>0</u><u>°</u><u>.</u>

8 0
2 years ago
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