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Verdich [7]
3 years ago
15

Let the sample space beUpper S equals StartSet 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10 EndSet

S={1, 2, 3, 4, 5, 6, 7, 8, 9, 10}.Suppose the outcomes are equally likely. Compute the probability of the eventUpper E equals StartSet 1 comma 2 comma 4 comma 6 EndSetE={1, 2, 4, 6}.
Mathematics
1 answer:
AleksAgata [21]3 years ago
7 0

Answer:

The probability would be 0.40

Step-by-step explanation:

Given,

The elements in set S are,

1, 2, 3, 4, 5, 6, 7, 9, 10,

Number of elements = 10,

Since, the outcomes are equally likely,

And, we know that,

\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

So, the probability of getting 1, 2, 4, or 6 = \frac{4}{10}=0.40

Hence, the probability of the event E = {1, 2, 4, 6} is 0.40.

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Step-by-step explanation:

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3 years ago
The graph below shows the value of Edna's profits f(t), in dollars, after t months:
umka21 [38]
Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), x=6 and x=18 are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
x=6
x-6=0
x=18
x-18=0

(x-6)(x-18)=x^{2}-6x-18x+108
=x^{2}-24x+108

Now that we have our quadratic function, we are going to use the average formula: m= \frac{f(9)-f(3)}{9-3}
where
f(9) is the function evaluated at  the <span>9th month
</span>f(3) is the function evaluated at the 3rd month 

m= \frac{f(9)-f(3)}{9-3}
m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}
m= \frac{-27-45}{6}
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6 0
3 years ago
Read 2 more answers
Which of these points lies on the circle with the center (2,3) and radius 2?
yan [13]

Answer:

The answer to your question is the letter A.

Step-by-step explanation:

Data

Center = (2, 3)

radius = 2

Process

1.- Find the equation of the line

              (x - h)² + (y - k)² = r²

-Substitution

              (x - 2)² + (y - 3)² = 2²  

-Simplification

              (x - 2)² + (y - 3)² = 4

-Evaluate the points in the equation

A. (4, 3)

              (4 - 2)² + (3 - 3)² = 4

                   2² + 0 = 4

                           4 = 4     This point lies in the circle

B (-1, 0)

              (-1 - 2)² + (0 - 3)² = 4

                        -3² + (-3)² = 4

                          9 + 9 = 4   This point is not part of the circle

C. (1, 3)

              (1 - 2)² + (3 - 3)² = 4

                 (-1)² + (0)² = 4

                            1 = 4          This point is not part of the circle

D. (3, 4)

              (3 - 2)² + (4 - 3)² = 4

                     1² + 1² = 4

                            2 = 4          This point is not part of the circle

5 0
3 years ago
Read 2 more answers
What is 3a squared multiplied by 5a
Travka [436]
3a^2 *5a \to \boxed{15a^3}
6 0
4 years ago
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