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Verdich [7]
3 years ago
15

Let the sample space beUpper S equals StartSet 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10 EndSet

S={1, 2, 3, 4, 5, 6, 7, 8, 9, 10}.Suppose the outcomes are equally likely. Compute the probability of the eventUpper E equals StartSet 1 comma 2 comma 4 comma 6 EndSetE={1, 2, 4, 6}.
Mathematics
1 answer:
AleksAgata [21]3 years ago
7 0

Answer:

The probability would be 0.40

Step-by-step explanation:

Given,

The elements in set S are,

1, 2, 3, 4, 5, 6, 7, 9, 10,

Number of elements = 10,

Since, the outcomes are equally likely,

And, we know that,

\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

So, the probability of getting 1, 2, 4, or 6 = \frac{4}{10}=0.40

Hence, the probability of the event E = {1, 2, 4, 6} is 0.40.

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A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{(n-r)!r!}

Given : Total multiple-choice questions  = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= ^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84

No. of ways to answer 4 open-ended problems

= ^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= 84\times15=1260

Hence, the correct answer is option A) 1260

5 0
3 years ago
Can you please give the answer for this problem? :<br> 18+11v=w-13t for t
Kay [80]
18+11v=w-13t
18+11-w=-13t
13t=w-11v-18
t=1/13w - 11/13v - 1 5/13

Hope this helps :)
6 0
3 years ago
X=5 and y=7 for algebraic expression 2(4x-3) + 6(3y-5)
garik1379 [7]

Answer:

130

Step-by-step explanation:

2(4x - 3) + 6(3y - 5)

2(4 × 5 - 3) + 6(3 × 7 - 5)

2(20 - 3) + 6(21 - 5)

2(17) + 6(16)

34 + 96

130

8 0
3 years ago
Read 2 more answers
A ball is dropped from a height of 5ft and bounces to 60% of I?ts previous height in each subsequent bounce
Gelneren [198K]

Answer:

Im assuming youre trying to answer what is the 60% height, it would be 3ft

Step-by-step explanation:


7 0
4 years ago
Consider the two functions shown here. What is the rate of change of each function?
Katarina [22]
The rate of change is the same as the slope.

Let's find the slope of function 1 using the Rise Over Run rule.
The rise is 2 and run is 1. So your rate of change is 2/1 or 2 for function 1

Function 2 is a y = mx + b equation, the slope is usually "m" or before the x
y = 1/2x + 7
1/2 is your rate of change for function 2
7 0
3 years ago
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