F = 1.8C + 32
С = -10 ⇒ F = 1.8·(-10) + 32 = 14 ⇒
(-10, 14)С = 0 ⇒ F = 1.8·(0) + 32 = 32 ⇒
(0, 32)
С = 10 ⇒ F = 1.8·(10) + 32 = 50 ⇒
(10, 50)С = 20 ⇒ F = 1.8·(20) + 32 = 68 ⇒
(20, 68)
12 2 +16 2 = D2
D2= 144+256
D2= 400
D2= 400
Answer:
Interest in 3 years = $456.52
Step-by-step explanation:
As we know the the formula of compound interest
Total amount = 
Here n = number of times amount is compounded
r = rate of interest
t = period
Here A = $2500
r = 0.0575
n = 1 (compounded annually)
t = 3 years
Therefore amount after 3 years
P =2500(1.0575)³
= 2500×1.18
= $2956.52
We have to calculate the interest then
Interest = $2956.52-$2500 = $456.52
So after 3 years interest gained = $456.52
It is th top right answer because AB = DE but the others are not but length doesn't effect the angles of abcdef
Given:
<span>11 11.5 10.5 17 14.5 14.5 18 17 19
Arrange in chronological order from least to greatest.
10.5 ; 11 ; 11.5 ; 14.5 ; 14.5 ; 17 ; 17 ; 18 ; 19
</span><span>I used an online lower and upper fence calculator to get the necessary data.
Minimum: 10.5
Maximum: 19
Q1: 11.25
Q2 or median: 14.5
Q3: 17.5
Interquartile range can be solved by subtracting the value of Q1 from the value of Q3
IQR = Q3 - Q1
IQR = 17.5 - 11.25
IQR = 6.25 CHOICE A. </span>
