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gladu [14]
3 years ago
6

Ppppppllease help meeeeee :)

Mathematics
2 answers:
nekit [7.7K]3 years ago
5 0
I think is c because you just flipping the the letters and It should be the same answer ...but I’m not sure....
enyata [817]3 years ago
4 0
The answer is 76 there isn’t another number being included therefore it would be 76
answer=76
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Select the correct answer. Choose the system of inequalities that best matches the graph below. у 2 4 3 X Х -6 3 -2 -1 ON 2 -1 -
AnnZ [28]

Answer:

There is not graph

Step-by-step explanation:

8 0
3 years ago
A rectangle measures 2 1/2 meters by 1 3/4 meters. What is its area?
REY [17]

Answer:

4 3/8

Step-by-step explanation:

1. We can use the formula

<em>Area = L (length) x W (width)</em>

2. The area is unknown so we can substitute it for<em> a</em>

<em>   </em>The length and width are both known, so we can plug them in.

<em>a= 2 1/2 x 1 3/4</em>

3. Solve by multiplying

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3 years ago
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3 years ago
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There are 7 seniors on student council. Two of them will be chosen to go to
Norma-Jean [14]

Answer:

Combination; number of ways = 21

Step-by-step explanation:

5 0
4 years ago
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What is the correct equilibrium constant expression for this equation? 2 upper C upper o upper F subscript 2 (g) double arrow up
Alekssandra [29.7K]

The correct equilibrium constant expression for this equation is;

\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}

Given

Consider the equation below.

\rm {2COF_2(g)}\rightleftharpoons C0_2(g)+CF_4(g)

<h3>What are Species?</h3>

In an equilibrium constant expression, you do not include the solid substances; only gases and dissolved substances.

<h3>Equilibrium constant expression;</h3>

It is the quotient of the product of the concentrations of the species on the right-hand side of the equilibrium equation, each raised to its corresponding coefficient, and the product of the concentrations of the species on the left-hand side, each raised to its corresponding coefficient.

Therefore,

The correct equilibrium constant expression for this equation is;

\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}

Hence, the correct equilibrium constant expression for this equation is;

\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}.

To know more about Equilibrium constant click the link is given below.

brainly.com/question/19240570

3 0
2 years ago
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