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Oxana [17]
3 years ago
7

Round 13 to the nearest 10.

Mathematics
2 answers:
mr Goodwill [35]3 years ago
3 0

Round down to 10. 13 goes to 10.

frozen [14]3 years ago
3 0

You round numbers to the nearest 10 based on the unit value. If it's 5 or above (5, 6, 7, 8, 9), you round up, to the next ten. If it's 4 or below (4, 3, 2, 1, 0), you round down to the same ten.

So 13 has a unit value of 3, so you round down to the same ten, which is literally just the number 10.

Therefore, your final answer is 10 :)

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Simplify<br>5/2y-1 - 6/3y-1​
Kipish [7]

Answer:

Step-by-step explanation:

First Group like terms:

5/2y-6/3y-1-1

Add similar elements:5/2y-6/3y=1/2y

1/2y-1-1

1/2y=y/2

=y/2-1-1

=y/2-2

6 0
3 years ago
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
Halp how to factor 4x-2
denis-greek [22]

Answer:

2(2−1)

Step-by-step explanation:

4−2

Grouping

Common factor

4−2

2(2−1)

Solution

2(2−1)

7 0
2 years ago
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HELP ASAP
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D=dollars earned
T=time spent painting the fence.

(1,5) (2,10) (3,15)

D=5T
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3 years ago
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