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sesenic [268]
4 years ago
10

How do printers work.

Computers and Technology
2 answers:
natulia [17]4 years ago
7 0
This question really depends on the type of printer device. There are the following kinds of printers:
Inkjet
Laser
Thermal
Dye Sublimation
Dot Matrix
Solid Ink

Each of these types of printers print in very different ways. I'm not going to get into depth about all of them, as that would take too much time. But what I can do is explain to you what a logical printer object is. So when you think of a printer, you think of the actual printer hardware. However, there are three distinct parts to a printer. These three parts are: the <em>print device, the driver, and the spooler</em>. Essentially what happens is that these three components communicate with one another in order to complete print jobs. So lets say I have a wireless network laser printer which is connected to a wireless access point, along with three other workstations. Then let's say that those three workstations want to send print jobs to the network printer. What happens is that all of those print jobs are <em>spooled</em>, meaning they are placed into a print queue. The driver then takes print jobs out of the print queue at the printer object's leisure. The driver then encodes the data from the print job into a language which the print device can understand, an example being PostScript. Then the driver sends that print job to the print device, and depending on what kind of printer you have, the method in which that print job is completed varies.
castortr0y [4]4 years ago
4 0
U can go to ur fav site and and press the print button if u have a printer
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Suppose you have an int variable called number. What Java expression produces the second-to-last digit of the number (the 10s pl
kobusy [5.1K]

Answer:

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Explanation:

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for the second expression int third_to_last = (number/100)%10; first divide the number by hundred and then get modulus by dividing by ten which will then give the third to last digit.

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The area of a rectangle is the rectangle's length times its width.
aliya0001 [1]

Answer:

Following are program to this question:

#include <iostream> //defining header file  

using namespace std;  

int main() //defining main method

{

   double len1,len2,wid1,wid2,area1,area2; //defining double variable

   cout << "Enter first rectangle length: "; //print message

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   cout << "Enter first rectangle width: ";//print message

   cin >> wid1; //input first rectangle width value

   area1 = len1*wid1; //calculate area and holds its value  

   cout << "Enter second rectangle length: ";//print message

   cin >> len2; //input second rectangle length value

   cout << "Enter second rectangle width: ";//print message

   cin >> wid2; //input second rectangle width value

   area2 = len2*wid2; //calculate area and holds its value  

   if(area1 > area2) //check condition area1 value is greater then area2

   {

    cout << "First rectangle area value is greater";//print message

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   else if(area2 > area1)//check condition area2 value is greater then area1

   {

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   else //else block

   {

       cout << "both rectangle area is same";//print message

   }

   return 0;

}

Output:

Enter first rectangle length: 3

Enter first rectangle width: 5

Enter second rectangle length: 5

Enter second rectangle width: 3

both rectangle area is same

Explanation:

The description of the above program can be described as follows:

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  • Otherwise, it will go to else if block, that checks area2 is greater then area1, it is will print second rectangle area is greater.  In the else section, it will print both equal areas.

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