h(x) = x g(x)
h'(x) = x g'(x) + (1)g(x)
h'(x) = x g'(x) + g(x)
Since g(x) = f^-1(x), then
g'(x) = 1/f'(x)
h'(x) = x/f'(x) + f^-1(x)
Therefore,
h'(5) = 5/f'(5) + f^-1(5).
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Answer:
a
Step-by-step explanation:
the green figure is the same as the blue figure.
Answer:
390
Step-by-step explanation:
(x+108) and (x+88) are supplementary angles. This means that they add to 180.
(x+108) + (x+88) = 180
Solve for x:
2x + 196 = 180
2x = -16
x = -8
