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3 years ago

Pls help asap ill give brainliest!

2 answers:

7 0

Equation: $3(x+4)=3x+11$

Can be simplified using distribution of parentheses: $3x+12=3x+11$

Now we subtract $3x$ from both sides and get: $12=11$

Which is false ( $12\neq11$ ) and therefore the equation has no solution $x=\emptyset$

Feel free to ask anything ;)

dedylja [7]3 years ago

3 0

<h3>Answer</h3>

$3 \times (x + 4) = 3x + 11$

$3x + 12 = 3x + 11$

That's impossible, cause 3x plus 12 can't be equal to 3x plus 11.

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A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

<u>Answer-</u>

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

$\binom{52}{9} = \frac{52!}{9!43!} = 3679075400$

∴P(3 white candies) = $\frac{1073233392}{3679075400} =0.29$

Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

$\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}$

$=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})$

$=(969)(45)(7)(5)(15)=22892625$

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

$\binom{52}{9}=\frac{52!}{9!43!} =3679075400$

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

$\frac{22892625}{3679075400} = 0.006$

6 0

3 years ago

A bag had 7 orange rocks , 6 green rock , 1 white rock ,7 black rocks , and 2 yellow you randomly pull a rock from the bag ,keep

daser333 [38]

Answer:

$Probability = \frac{7}{253}$

Step-by-step explanation:

Given

$Orange = 7$

$Green = 6$

$White = 1$

$Black = 7$

$Yellow = 2$

Required

Probability of selecting a yellow then orange rock

From the question, we understand that the probability is that of without replacement.

Since the yellow, is first picked.

We need to determine the probability of picking a yellow rock, first.

$P(Yellow) = \frac{n(Yellow)}{Total}$

$P(Yellow) = \frac{2}{7 + 6 + 1 + 7 + 2}$

$P(Yellow) = \frac{2}{23}$

The rock has reduced by 1;

Next is to determine the probability of picking an orange rock

$P(Orange) = \frac{n(Orange)}{Total - 1}$

$P(Orange) = \frac{7}{7 + 6 + 1 + 7 + 2- 1}$

$P(Orange) = \frac{7}{22}$

The required probability is calculated as thus:

$Probability = P(Yellow) * P(Orange)$

$Probability = \frac{2}{23} * \frac{7}{22}$

$Probability = \frac{14}{506}$

$Probability = \frac{7}{253}$

4 0

3 years ago

(I WILL GIVE DA BRAINLIEST) Mackenzie and Roger both leave the park at the same time walking in opposite directions. Mackenzie w

Margaret [11]

(5+6=miles per hour)
i hope this helps
so look...
m=miles
(5m+6=m)<------ answer
hope this helps

5 0

3 years ago

Maria started with $10. She has been saving $3 dollars each week to buy a softball bat. The amount of money Maria has depends on

Mama L [17]

The correct answer is b as she starts with 10 and keeps on added 3 dollars per week

3 0

3 years ago

What is the coefficient of the x9y-term in the binomial expansion of (2y + 4x3)4?

Strike441 [17]

The answer to your question is D. 512

3 0

3 years ago

Read 2 more answers