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attashe74 [19]
3 years ago
12

Answer the questions please

Mathematics
1 answer:
Drupady [299]3 years ago
4 0

Answer:

4.  988 people

5. a. 7 quarters

    b. 6 quarters 2 dimes 1 nickel

    c. 5 quarters 5 dimes

    d. 4 quarters 7 dimes 1 nickel

1.  $65.65, $5.05

2. $7.70, $15.40

3. a. 7 quarters

    b. 6 quarters 2 dimes 1 nickel

    c. 5 quarters 5 dimes

    d. 4 quarters 7 dimes 1 nickel

4. 31 bags

5. $30, $4.50

Step-by-step explanation:

4. take value times percent.

5. think coins

1. find difference then divide by number of days (13)

2. multiply by 1/3 then find difference.

3. think coins

4. find area then divide by 200

5. just break the problem down and go quarter by quarter.

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What are least common multiples
Dvinal [7]


A common multiple is a number that is a multiple of two or more numbers. The common multiples of 3 and 4 are 0, 12, 24, .... The least common multiple (LCM) of two numbers is the smallest number (not zero) that is amultiple of both.

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3 years ago
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Help??
julsineya [31]
You would use the equation 

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3 0
3 years ago
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I need help please and thank you
s344n2d4d5 [400]

Answer:

20 degrees.

Step-by-step explanation:

The 3 angles of a triangle add up to 180 degrees.

Therefore the third angle in this triangle

= 180 - (120 + 40)

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4 0
2 years ago
8. Is the following statement true or false? Justify your conclusion. If a and b are nonnegative real numbers and a + b =0, then
atroni [7]

Answer:

If a + b = 0 then a = 0 and b =0

a  | b | a + b (answer)

0 | 0 | 0

0 | 1  | 1

0 | 2 | 2

1  | 0 | 1

2 | 0 | 2

1  | 1  | 2

2 | 1  | 3

 

Step-by-step explanation:

Considering the following conditions for the real numbers:

a\geq 0\\b\geq 0

Following the rules of these in-equations, it is possible to deduce:

a + b \geq 0

Then, if the proposed statement is:

a + b = 0

The conditions above shall comply the requirements established, but first, analyzing the statement:

If a \geq 0 and b \geq 0 then a + b \geq a, a + b \geq b and a + b \geq 0.

If a = 0 and b a non negative real number, then a + b \geq b, but because to a = 0, then a + b = b. Due to the commutative property of sums, the same behavior will be presented if b = 0 and a a non negative real number.

According to that, if  a + b = 0, then a = 0 and b = 0.

7 0
3 years ago
If , what is the value of x? 2 3 4 6
Serggg [28]
If what ? What is the If part, so I can help answer your question.
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