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uysha [10]
3 years ago
12

How to do word problem with addition or subtraction of integers

Mathematics
1 answer:
Semenov [28]3 years ago
4 0
For Addition, if the signs are the same, you add and keep the sign. And if they are different, you subtract and keep the sign of the greater absolute value.
For Subtraction, You change the subtraction sign to the addition one and then follow the rules of addition, above.
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The height of the sail on a boat is 7 feet less than 3 times the length of its base. If the The area of the sail is 68 square fe
Dima020 [189]

Step-by-step explanation:

It is given that,

The height of the sail on a boat is 7 feet less than 3 times the length of its base.

Let the length of the base is x.

ATQ,

Height = (3x-7)

Area of the sail is 68 square feet.

Formula for area is given by :

A=lb\\\\68=x(3x-7)\\\\3x^2-7x=68\\\\3x^2-7x-68=0

x = 8 feet and x = -3.73 feet

So, length is 8 feet

Height is 3(8)-7 = 17 feet.

So, its height and the length of the base is 17 feet and 8 feet respectively.

3 0
3 years ago
Write the square of the binomial as a polynomial: (-1 1/3p + 6q)^2
Thepotemich [5.8K]

Answer:

\frac{16}{9}p² -16pq + 36q²

Step-by-step explanation:

Given

(- \frac{4}{3}p + 6q)²

= (- \frac{4}{3}p + 6q)(- \frac{4}{3}p + 6q)

Each term in the second factor is multiplied by each term in the first factor, that is

- \frac{4}{3}p(- \frac{4}{3}p + 6q) + 6q(- \frac{4}{3}p + 6q)

= \frac{16}{9}p² - 8pq - 8pq + 36q² ← collect like terms

= \frac{16}{9}p² - 16pq + 36q²

5 0
4 years ago
Use the number line below, where RS=7y+3, ST=2y+9, RT=14y-8<br>a. What is the value of y?<br>y=
Ilia_Sergeevich [38]
RS+ST= RT
(7Y+3)+(2Y+9)= 14Y-8
9Y+12=14Y-8
5Y=20
Y=4
8 0
3 years ago
Pls help <br> Are they SSS or SAS??
8090 [49]

Answer:

I think they are SAS but I'm not sure

7 0
3 years ago
Determine the relationship between the two vecors
asambeis [7]

Answer:

Step-by-step explanation:

Since there exists a scalar  

λ

λ

(namely  

λ=a⋅b

λ=a⋅b

) such that  

b=λa

b=λa

, the directions of the two vertices are the same (they are collinear). This implies that  

|a⋅b|=|a||b|

|a⋅b|=|a||b|

.

So,  

|a|=|(a⋅b)b|=|a||b||b|

|a|=|(a⋅b)b|=|a||b||b|

which implies that  

|b|=1

|b|=1

6 0
3 years ago
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