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3 years ago

Solve (x 2 < 5) ∩ (x - 7 > -6).

Mathematics

1 answer:

Blababa [14]3 years ago

5 0

X + 2 < 5 and x - 7 > -6
x < 5 - 2 and x > -6 + 7
x < 3 and x > 1

Therefore, solutin is {x | 1 < x < 3}

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Need some math help thanks in advance!

vredina [299]

Answer:

x = 10

y = 6

Step-by-step explanation:

Vertical Angle Theorem: When two straight lines intersect, the opposite vertical angles are always equal to each other.

⇒ m∠1 = m∠3 and m∠2 = m∠4

⇒ m∠1 = m∠3

⇒ 10x = 100

⇒ x = 10

Linear pair: Two adjacent angles which sum to 180°.

⇒ m∠1 + m∠2 = 180°

⇒ m∠3 + m∠4 = 180°

⇒ 100 + 10y + 20 = 180

⇒ 120 + 10y = 180

⇒ 10y = 60

⇒ y = 6

7 0

2 years ago

Please help brainliest (Algebra 1)

den301095 [7]

Answer:

B - 11 > (w - 4)²

C - y < 3⁴

D - 5 + 9 < 5 · 9

are your correct answers

Step-by-step explanation:

x² - 5x + 6 and z + 11 / 2z - 1 are equalities phrases and rest of them will be inequalities.

HOPE THIS HELPS YOU

Follw me = 10 thanks

Mark as brainliest = 10 thanks

1 thanks to me = 2 thanks

3 0

2 years ago

What is the difference? 5/3-1/2 A. 4 B. 7 C. 7/6 D. 7/0 = undefined

Fofino [41]

The answer is: [C]:  " ⁷/₆ " .
____________________________________
Note:
____________________________________
(5/3) - (1/2) = ? ;
____________________________________
The LCD (lowest common denominator) of "2 and 3" is "6" ;

So we need to rewrite EACH fraction in the problem as a fraction with "6" in the denominator ;
____________________________
(5/3) = (?/6) ? ; (6÷3=2) ; (5/3) = (5*2)/(3*2) = 10/6 ;
____________________________
(1/2) = (?/6) ? ; (6÷2=3) ; (1/2) = (1*3)/(2*3) = 3/6 ;
____________________________
Rewrite the problem: "   (5/3) - (1/2) " ; as:
____________________________
10/6 - 3/6 ;
____________________________________________
  10/6 - 3/6 = (10 - 3) / 6 = (7/6) = 1 ⅙ .
____________________________________________
The answer is: " ⁷/₆ " ; or, write as: " 1 ⅙ " ; which corresponds to:
______________________________________________________
Answer choice: [C]: " ⁷/₆ " .
____________________________________________

5 0

2 years ago

Find the product of the complex numbers. Express your answer in trigonometric form. z1 = 5(cos(25) + isin(25)) z2 = 2(cos(80) +

zmey [24]

solution:

Z1 = 5(cos25˚+isin25˚)

Z2 = 2(cos80˚+isin80˚)

Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)

Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }

Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}

(i^2 = -1)

Cos(A+B) = cosAcosB – sinAsinB

Sin(A+B) = sinAcosB + cosAsinB

Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)

Z1.Z2 = 10(cos105˚+ isin105˚)

5 0

3 years ago

HELPPO ME PLEASEE!!!!!!

ElenaW [278]

Answer:

Here,

x + 25° + 3x + 95° + 80°=360° (Sum of angles of a quadrilateral is 360°)

or,x+3x + 25° + 95° + 80° =360°

or,4x + 200 = 360°

or,4x = 360 - 200

or,4x = 160

or,x = 160÷4

or,x = 40

Now,

Angle K = (x + 25)° = 40 + 25° = 65°

Angle L = 3x° = 3 × 40° = 120°

4 0

2 years ago