I need help... ASAP please
1 answer:
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Answer:
√7
Step-by-step explanation:
Let :
AC = x
BD = y ; AD = 3 - y
Since, AD = BC
Then BC = 3 - y
Taking △BDC a d applying Pythagoras
Hypotenus² = opposite² + adjacent²
BC² = CD² + BD²
(3 - y)² = (√3)² + y²
9 - 6y + y² = 3 + y²
-6y + y² - y² = 3 - 9
-6y = - 6
y = 1
AD = 3 - y ; AD = 3 - 1 = 2
Taking △ADC
AC² = CD² + AD²
AC² = (√3)² + 2²
AC² = 3 + 4
AC² = 7
AC = √7
We have to functions, namely:
So the problem is asking for the smallest positive integer for
so that 
is greater than the value of 
, that is:
Let's solve this problem by using the trial and error method:
So starting from 1 and increasing it in steps of one we find that:
when
That is, the smallest positive integer for so that the function is greater than is 4.
So the problem is asking for the smallest positive integer for
Let's solve this problem by using the trial and error method:
So starting
when
That is, the smallest positive integer for