Answer:
0.4 kmffffffffffffffffffffffffffffffffff
Answer:

which agrees with the first answer in the list of possible options.
Step-by-step explanation:
We can use the fact that the addition of all four internal angles of a quadrilateral must render
. Then we can create the following equation and solve for the unknown "h":

Therefore the angles of this quadrilateral are:

Prove:
Using mathemetical induction:
P(n) = 
for n=1
P(n) =
= 6
It is divisible by 2 and 3
Now, for n=k, 
P(k) = 
Assuming P(k) is divisible by 2 and 3:
Now, for n=k+1:
P(k+1) = 
P(k+1) = 
P(k+1) = 
Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also
divisible by 2 and 3.
Hence, by mathematical induction, P(n) =
is divisible by 2 and 3 for all positive integer n.
Answer:

Step-by-step explanation:

What you can do in this case is a rule of three to determine the length of each bow.
We have then:
1/4 ---> 2
x ------> 1
Clearing x we have:
x = (1/2) * (1/4)
x = 1/8
Answer:
the length of ribbon in each bow is
x = 1/8
Equivalently:
x = (1/4) / 2
Option 3