Answer:
i don't have the table so no one can answer
Step-by-step explanation:
The first, fourth and fifth ones are linear.
The second, third and sixth are all nonlinear.
You can tell this by the fact that their lead exponents are not 1.
Answer:

Step-by-step explanation:
Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

We identify the coefficients for the like terms, it comes
a = -2 and 16a = -32 (which is equivalent). So, we can write in
.

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

And we can write in 

Hope this helps.
Do not hesitate if you need further explanation.
Thank you