Answer:
Solution:
The formula to find the perimeter of the quadrilateral = sum of the length of all the four sides.
Here the lengths of all the four sides are 5 cm, 7 cm, 9 cm and 11 cm.
Therefore, perimeter of quadrilateral = 5 cm + 7 cm + 9 cm + 11 cm
= 32 cm
Answer:
there you go but im not sure . hope its helpful and good luck ;)
Answer:
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form 
or 
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
we have the point (-30,18)
so
x=-30, y=18
Find the value of k
substitute
Simplify
Divide by 6 both numerator and denominator
A) w + 7 = L
B) w * L = 120
A) w = L -7 then substituting this into B)
(L-7) * L = 120
L² -7L = 120
L² -7L -120 = 0
Solving by quadratic Formula:
L1 = 15
L2 = -8
If length = 15, then width = 8
1) question 18 of 20
-7x/5-(4y)=7
4y=-7x/5-(7)
y=-7x/20-(7/4).
if x=0 ⇒y=-7*0/20-7/4=-7/4 ⇒y-intercept is-7/4
fi y=0 ⇒ -7x/20-(7/4)=0
-7x/20=7/4
x=(7*20) / [4*-(7)]=-5 ⇒x-intercept is -5
Solution: D) x-intercept is -5 ; y-intercept is -7/4
Question 19 of 20
P₁=(x₁,y₁)
P₂=(x₂,y₂)
m=slope
m=(y₂-y₁) / (x₂-x₁)
Then:
A(1,7)
B(10,1)
m=(1-7) / (10-1)=-6/9=-2/3.
Solution: B)-2/3
Question 20 of 20:
y-y₀=m.(x-x₀)
A(4,3)
B(-4,-2)
m=(-2-3) / (-4-4)=-5/-8=5/8
y-3=(5/8).(x-4)
y=5x/8-(20/8)+3
y=5x/8-(20/8)+24/8
y=5x/8+(4/8)
y=5x/8+1/2
solution: B) y=5x/8+1/2
