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umka21 [38]
3 years ago
9

How many solutions does 6a- 3a - 6 = 2 + 3 have?

Mathematics
1 answer:
lana [24]3 years ago
4 0
Just one. the solution is 11/3
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What is the radius of a cylinder with a volume of 3,165.12 cubic centimeters and a height of 7 centimeters?
leonid [27]

Answer:

Radius = 12 cm

Step-by-step explanation:

Given:

Volume of the cylinder is, V=3165.12 cm³

Height of the cylinder, h= 7 cm

Let the radius be r

Using the formula for volume of cylinder,

V=\pi r^2h

Plug in 3165.12 for V, 7 for h and solve for r.

3165.12=\pi r^2(7)\\3165.12=\frac{22}{7}\times 7\times r^2\\3165.12=22r^2\\r^2=\frac{3165.12}{22}\\r^2=143.869\\r=\sqrt{143.869}=11.99\approx=12\textrm{ cm}

Therefore, the radius of the cylinder is nearly 12 cm.

7 0
3 years ago
Alexa surveyed 7 students and found 2 like scary movies.based on this information how many students would like scary movies out
Fudgin [204]
The answer is 10 10 students liked scary movies out of 35
6 0
3 years ago
Eleven members of the Middle School Math Club each paid the same amount for a guest speaker to talk about problem solving at the
Ilia_Sergeevich [38]
The correct answer for the question that is being presented above is this one: "<span>The missing digit is 3."</span>

The missing digit is represented by A  ⇒  $1A2, where A represents a whole number from 0 to 9.

Try substituting any number from 0 to 9 for A (the middle digit or tens place) , then divide by 11 members.

<span>Option 2:  A = 3  ⇒  $1 </span><span>3 </span>2
$ 132 ÷ 11 = $12

The only one-digit that gives a whole number quotient when it takes the place of tens digit in $1 __2  is<span> 3.</span><span>   Because $ 132 ÷ 11 = $ 12. (Option 2)</span>

The missing digit is 3.
6 0
3 years ago
Use the power property to rewrite log3x9.
Kitty [74]

Answer:

\log _3\left(x^9\right)=9\log _3\left(x\right)

Step-by-step explanation:

Given the expression

\log _3\:x^9

now rewriting the expression

\log _3\:x^9

\mathrm{Apply\:log\:rule\:}\log _a\left(x^b\right)=b\cdot \log _a\left(x\right),\:\quad \mathrm{\:assuming\:}x\:\ge \:0

=9\log _3\left(x\right)

Therefore,

\log _3\left(x^9\right)=9\log _3\left(x\right)

9 0
2 years ago
Read 2 more answers
Pls help I need help plsss
cupoosta [38]
Whats up? What do you need help with
4 0
3 years ago
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