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serg [7]
3 years ago
12

Use the net to find the surface area of the prism 6ft 11ft 6ft 11ft 8ft

Mathematics
2 answers:
goblinko [34]3 years ago
8 0
If I am correct, the surface area of the prism should be 404ft.
mylen [45]3 years ago
3 0

Answer:  The toral surface area of the prism is 404 sq ft.

Step-by-step explanation:  We are given to find the surface area of the prism using the net of the prism shown.

The surface area of the prism is equal to the sum of the areas of all the rectangles in the net.

As shown in the net, there are four rectangle with dimensions as follows:

(a) Two rectangles of 6 ft by 8 ft. The area of these rectangles will be

A = 2 × 6 × 8 = 96 sq. ft.

(b) One rectangle of 11 ft by (6 + 8 + 6 = 20) ft. The area of this rectangle will be

B = 11 × 20 = 220 sq. ft.

(c) One rectangle of 11 ft by 8 ft. The area of this rectangle will be

C = 11 × 8 = 88 sq ft.

Thus, the total surface area of the prism is given by

A + B +C = 96 + 220 + 88 = 404 sq ft.

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The answer is:  " f ⁻¹(x)  = \frac{x}{2}  + 5 " . 
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Explanation:

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Given the function:  " f(x) = 2x <span>− 10 " ;  Find the "inverse function" .

Let "f(x)" be represented by "y" ; and rewrite:

    y = 2x </span><span>− 10 ; 

Change the "y" to an "x" ;  and change to "x" to a "y" ; as follows:
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    x = 2y </span><span>− 10 ; 

Now, rewrite this equation, in "slope-intercept form";  that is;  "y = mx + b" ; 

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 We have: 
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   " x = 2y </span><span>− 10 " ; 

Add "10" to each side of the equation; as follows:

    x + 10 = 2y </span><span>− 10 + 10 ; 

to get:

     x + 10 = 2y ; 

</span>↔  2y = x + 10 ;
<span>
Now, divide each side of the equation by "2" ; 
       to isolate "y" on one side of the equation (as a single variable); 
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</span>→  2y / 2 = (x + 10) / 2 ; 
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to get: 

</span>→    y = (x/2)  + (10/2) ; 

→    y = (x/2) + 5 ; 
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Now, rewrite the equation, by substituting:  " f </span>⁻¹(x) " ;  in place of the "y" ;                     to indicate that this function is an "inverse function; as follows:
 
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The answer is:  " f ⁻¹(x)  = \frac{x}{2}  + 5 " . 
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