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Arturiano [62]
3 years ago
15

Type the standard form of three hundred thousand two hundred one

Mathematics
2 answers:
leonid [27]3 years ago
5 0

━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━  

Standard form is numbers only.

Examples of standard numbers are 4, 225, or 9,002

A thousands number has 4 digits.

A hundreds number has 3 digits.

A tens number has 2 digits.

A regular number has 1 digit (itself).

Three hundred means 300.

Three hundred thousand, would be 300 times 1,000 (one thousand), or adding 3 zeros.

Two hundred is 200.

One is 1.

300 times 1,000 is 300,000.

300,000 and 200 is 300,200.

If the ones digit has a 1, then the number is 300,201.

Three hundred thousand, two hundred one written in standard form is 300,201.

━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━  

Irina18 [472]3 years ago
4 0

Answer:

300,201

Step-by-step explanation:

Standard form is written in digit form.

Three hundred thousand two hundred one would be 300,201 in standard form.

Hope this helps!

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The value of y varies directly as the square of x and y=27 when x=9. Find the equation represents this relationship. Report the
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Answer:

The relation between x and y is

y=\frac13 x^2

Step-by-step explanation:

Given that,

The value of y varies directly as the square of x.

y\propto x^2

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where r is constant of proportional.

Given that,

y= 27 and x=9

Plug y= 27 and x=9 in above relation

y=rx^2

\therefore 27=r(9)^2

\Rightarrow 27 = r.81

\Rightarrow r=\frac{27}{81}

\Rightarrow r=\frac{1}{3}

The relation between x and y is

y=\frac13 x^2

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The diagram shows the sector of a circle with the centre O and radius 6cm.
cricket20 [7]

Answer:

Area of the shaded region = 1.92 cm²

Step-by-step explanation:

From the picture attached,

Area of the shaded region = Area of the sector OMN - Area of the triangle OMN

Area of sector OMN = \frac{\theta}{360}(\pi r^{2})

Here, θ = Central angle of the sector

r = radius of the sector

Area of sector OMN = \frac{50}{360}(\pi )(6)^2

                                  = 15.708 square cm

Area of ΔOMN = 2(ΔOPN)

Area of ΔOPN = \frac{1}{2}(OP)(PN)

Area of ΔOMN = OP × PN

In ΔOPN,

sin(25°) = \frac{PN}{ON}

PN = ONsin(25°)

     = 6sin(25°)

     = 2.536 cm²

cos(25°) = \frac{OP}{ON}

OP = ONcos(25°)

OP = 6cos(25°)

OP = 5.438 cm

Area of ΔOMN = 2.536 × 5.438

                         = 13.791 cm²

Area of the shaded region = 15.708 - 13.791 = 1.917 cm²

                                             ≈ 1.92 cm²

3 0
3 years ago
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