4 years ago

8.75 in 2.4 in 2.4 in 8.75 in Find the perimeter of the rectangle

Mathematics

1 answer:

Lapatulllka [165]4 years ago

8 0

All you need to do is add them all together and the answer is 22.3 :)

You might be interested in

0=-5n-2nI need help getting this answer

Lynna [10]

For your equation n = 0 l = -5/2

7 0

3 years ago

Help on number 2 please

Katarina [22]

Answer:

y=12.73 x=9

Step-by-step explanation:

3 0

3 years ago

A cake recipe requires cups of flour to make 1 cake. How many cakes can be made by a baker who has 16 cups of flour?

nikitadnepr [17]

Answer:

3 cakes

You need to add 4.5 until you get the closest you can get to 16 with out going over.

6 0

3 years ago

A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate

Shkiper50 [21]

The amount of salt in the tank changes with rate according to

$Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)$

$\implies Q'+\dfrac Q{300+3t}=4$

which is a linear ODE in $Q(t)$ . Multiplying both sides by $(300+3t)^{1/3}$ gives

$(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}$

so that the left side condenses into the derivative of a product,

$\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}$

Integrate both sides and solve for $Q(t)$ to get

$(300+3t)^{1/3}Q=(300+3t)^{4/3}+C$

$\implies Q(t)=300+3t+C(300+3t)^{-1/3}$

Given that $Q(0)=100$ , we find

$100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}$

and we get the particular solution

$Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}$

$\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}$

5 0

3 years ago

The equation of the graphed line is x + 2y = 5. What is the x-intercept of the graph?

alexdok [17]

If you have to find x-intercept, then you have to equate y to 0. Thus,

when y=0, x+2·0=5 and x=5.

Point (5,0) is x-intercept.

Answer: (5,0)

6 0

3 years ago

Read 2 more answers