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3 years ago

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!

Mathematics

2 answers:

valina [46]3 years ago

6 0

Answer:

(images to help with graph are below)

Step-by-step explanation:

okay! so once you get the hang of this, it is super super easy.

so the y-intercept is a point on that long line going up and down on the graph. it shows where the line intersects the middle!

so here it says that the y-intercept (y-int for short) is 2. so we will simply mark a little point on 2.

now the slope. the slope is -4. this can be written as -4/1. the -4 is on the top so i represents the y values. and the 1 is on the bottom so it represents the x values.

we know that when graphing, x goes from side to side and y goes up and down.

if an x value is positive you move it to the right (forwards), if it is negative you move it to the left (backwards). if a y value is positive you move it upwards, if it is negative you move it downwards. so we want to start graphing with our x.

The x value is 1 (because it is in the bottom of the slope! -4/1!). So we will move one point from the y-int (the point we marked).

Now for the y values. The y value is -4 (again, taken from the -4/1. the top number is the y value). FROM THE PLACE WE LEFT OFF FOR THE X VALUES (we left off at point (1,2) because we moved it one to the right!), we will move 4 points DOWN because it is negative (-4). Mark this place with a dot!

We should now have the points (0,2) and (1,-2) marked with a dot. draw a line through the 2 dots! this is ur finished graph. notice how the line intersects the middle on the y-intercept!! that will always happen.

Lastly, the equation! the formula for slope intercept form is y=mx+b

m is always your slope. b is your y-int. and y and x stay blank (for now. in the future you might use those spots). so simply fill in m and b!

the slope is -4. so m = -4

the y-int is 2. so b = 2

the finished equation should look like this:

y = -4x + 2

I hope this helped !!!

alekssr [168]3 years ago

4 0

Someone else is answering the graph but the equation is y=-4x+2 -4 = slope 2 = y-intercept

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Help with line equations?

Alecsey [184]

First question

$line:~~~~y=x+3$

$curve:~~~~x^2+y^2=29$

now we have to replace the y of curve by the y of line, therefore

$x^2+(x+3)^2=29$

$x^2+x^2+6x+9=29$

$2x^2+6x+9-29=0$

$2x^2+6x-20=0$

we can multiply each member by $\frac{1}{2}$

$\boxed{\boxed{x^2+3x-10=0}}$

Now we have to find the roots of this funtion

$x^2+3x-10=0$

Sum and produc or Bhaskara

Then we find two axis

$\boxed{x_1=2~~and~~x_2=-5}$

now we replace this values to find the Y, we can replace in curve or line equation, I'll prefer to replace it in line equation.

$y=x+3$

$y_1=x_1+3$

$y_1=2+3$

$\boxed{y_1=5}$

$y_2=x_2+3$

$y_2=-5+3$

$\boxed{y_2=-2}$

Therefore

$\boxed{\boxed{P_1(2,5)~~and~~P_2(-5,-2)}}$
_______________________________________________________________

The second question give to us

$y=ax+b$

$P_1(2,13)$

$P_2(-1,-11)$

We just have to replace the value then we'll get a linear system.

point 1

$13=2a+b$

point 2

$-11=-a+b$

then our linear system will be

$\begin{Bmatrix}2a+b&=&13\\-a+b&=&-11\end{matrix}$

I'll multiply the second line by -1 and I'll add to first one

$\begin{Bmatrix}2a+(a)+b+(-b)&=&13+(-11)\\-a+b&=&-11\end{matrix}$

$\begin{Bmatrix}3a&=&24\\-a+b&=&-11\end{matrix}$

$\begin{Bmatrix}a&=&8\\-a+b&=&-11\end{matrix}$

therefore we can replace the value of a, at second line

$\begin{Bmatrix}a&=&8\\-8+b&=&-11\end{matrix}$

$\begin{Bmatrix}a&=&8\\b&=&-11+8\end{matrix}$

$\boxed{\boxed{\begin{Bmatrix}a&=&8\\b&=&-3\end{matrix}}}$

then our function will be

$\boxed{\boxed{y=8x-3}}$

_________________________________________________________________

The third one, we have

$line:~~~~y=3x-4$

$curve:~~~~y=x^2-2x-4$

This resolution will be the same of our first question.

Let's replace the y of curve by the y of line

$3x-4=x^2-2x-4$

$0=x^2-2x-4-3x+4$

therefore

$\boxed{\boxed{x^2-5x=0}}$

now we have to find the roots of this function.

$x^2-5x=0$

put x in evidence

$x*(x-5)=0$

$\boxed{x_1=0~~and~~x_2=5}$

then

$y=3x-4$

$y_1=3x_1-4$

$y_1=3*0-4$

$\boxed{y_1=-4}$

$y_2=3x_2-4$

$y_2=3*5-4$

$y_2=15-4$

$\boxed{y_2=11}$

our points will be

$\boxed{\boxed{P_1(0,-4)~~and~~P_2(5,11)}}$

I hope you enjoy it ;)

5 0

3 years ago

I need help please

LUCKY_DIMON [66]

Answer:

5/10 or 0.5

Step-by-step explanation:

step 1:find the least common denominator

4/5-3/10=

8/10-3/10=

step 2:subtract the numerators

8/10-3/10=5/10 or 0.5

hope this helps and PLEASE MARK ME BRAINLIEST.

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3 years ago

Molly can bake 3 cakes in 2 hours. How many cakes can she bake per hour?

just olya [345]

Answer: 1.5 cakes per hour

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Step2247 [10]

Answer:

Min - 42

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Q1 = 70

Q3 = 86

Step-by-step explanation:

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2 years ago

I need help please I don’t understand

Evgen [1.6K]

You don’t need to do the math, think logically.

35% is almost 33%.

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The closest choice is H. 22,400.

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3 years ago