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Scorpion4ik [409]
3 years ago
8

Please help! I will mark you as brainliest!

Mathematics
1 answer:
otez555 [7]3 years ago
5 0
What are u trying to do
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A skier is trying to decide whether or not to buy a season ski pass. a daily pass is $75. A season ski pass is $350. The skier w
pishuonlain [190]
Since the skier has to rent skis for 30 dollars per day with both passes, we can ignore it while solving the question.

A season pass is 350, while a daily pass is 75.

\frac{350}{75} = \frac{25\times 14}{25\times 3} = \frac{14}{3} = 4 \frac{2}{3}

So a seasonal pass is equivalent to having 4.6667 daily passes. And you can't buy 0.6667 of a pass.

So, if you went at least 5 days with a seasonal pass, then the seasonal pass would be less expensive than a daily pass.
6 0
3 years ago
HELP ASAP!!!! ILL GIVE POINTSS!!!!​
algol [13]
The answer is b
The way I do it is the area of the front back times 2 which is 2x4x2=16
Then top and bottom times 2 which is 4x8x2=64
Then left and right which is 2x8x2=32 then you add them all together so 16+64+32=112
Hope this helped :)
8 0
4 years ago
Bob took his family out to lunch. He bought 3 hot dogs and 2 hamburgers for $11. If the guy in front of him bought 2 hot dogs an
Dafna11 [192]

Answer:

Hotdog: $1.50

Hamburger: $3.25

Step-by-step explanation:

<em>You write down the 2 equations based off of the information as I did:</em>

Let x = cost of a hotdog

Let y = cost of a hamburger

<em>and so:</em>

<em />

3x + 2y = 11

2x + 4y = 16

<em />

<em>Now, we need to find x and y:</em>

<em>We will make both equations equal to y to compare them to each other.</em>

2y = 11 - 3x

y = 5.5 - 1.5x

4y = 16 - 2x

y = 4 - 0.5x

4 - 0.5x = 5.5 - 1.5x

x = $1.5

<em>Now plugging in x into the equation:</em>

2(1.5) + 4y = 16

3 + 4y = 16

4y = 13

y = $3.25

And so hotdog = $1.5 and hamburger = $3.25

<em />

<em />

6 0
3 years ago
Given 6(3x-4)-26=40 PLEASE HELP ME
GREYUIT [131]

Answer:

18x-24-26=40

18x-50=40

18x=90

x=90/18

x=5

4 0
3 years ago
Find the difference. (9/x^2-9x)-(6/x^2-81)
Sunny_sXe [5.5K]

The difference is  $\frac{3 x+81}{x(x-9)(x+9)}$

Explanation:

The expression is $\left(\frac{9}{x^{2}-9 x}\right)-\left(\frac{6}{x^{2}-81}\right)$

Removing the parenthesis, we have,

$\left\frac{9}{x^{2}-9 x}\right-\left\frac{6}{x^{2}-81}\right$

Factoring the terms $x^{2}-9 x$ and $x^{2}-81$, we get,

$\frac{9}{x(x-9)}-\frac{6}{(x+9)(x-9)}$

Taking LCM, we get,

$\frac{9(x+9)-6x}{x(x-9)(x+9)}}$

Simplifying the numerator, we get,

$\frac{9x+81-6x}{x(x-9)(x+9)}}$

Subtracting the numerator, we have,

$\frac{3 x+81}{x(x-9)(x+9)}$

Hence, the difference is $\frac{3 x+81}{x(x-9)(x+9)}$

7 0
3 years ago
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