Answer:
The amount invested at 9% is $93000
The amount invested at 10% is $303000
Step-by-step explanation:
Let the amount invested at 9% interest rate be x
And the amount invested at 10% rate be y
Simple Interest from x in a year = 0.09x
Simple Interest from y in a year = 0.1y
But y = 24000 + 3x
And the sun of the interests, 0.09x + 0.1y = 38670
Now we have a simultaneous eqn
y = 24000 + 3x (eqn 1)
0.09x + 0.1y = 38670 (eqn)
Substitute y into eqn 2
0.09x + 0.1(24000 + 3x) = 38670
0.09x + 2400 + 0.3x = 38670
0.39x = 38670 - 2400
x = 36270/0.39 = $93000
y = 24000 + 3x = 24000 + 3 × 93000 = $303000
You take the amount paid and divide it by the amount of cheese. So 10.50 divided by 2.5 equals 4.2 and 12.60 divided by 3 equals 4.2 meaning that one pound of cheese costs $4.20
A circular concrete slab is a cylinder. Vol = pi%2Ar%5E2%2Ah
in this cylinder:
r = 18%2F2 = 9 ft
h = 3%2F12 = .25 ft
:
Find the volume in cu/ft:
V = pi%2A9%5E2%2A.25
V = 63.61725 cu/ft
:
Change to cubic yds; (1 cu/yd = 27 cu/ft) and multiply by $40:
Cost = 63.61725%2F27 * 40
Cost = $94.25
In practical terms , they may require you to buy 3 cu/yds , which is $120
Yan na po
304 would be the correct answer
Answer:
Set up the equation. On a piece of paper, write the number being divided on the right, under the division symbol, and the number doing the division to the left on the outside. ...
Divide the first digit. ...
Divide the first two digits. ...
Enter the first digit of the quotient.
hope this helps :)
