Question

The probability of reaching a certain point value in a popular video arcade game is listed in the table. Given that the table is a probability distribution, what is the mean, u? 100 200 300 400 500 600 700 800 P(x) 0.180 0.051 0.227 0.113 0.090 0.099 0.165 0.075

Answer 1

Answer:

We are given the below probability distribution table:

x                        P(x)

100                   0.180

200                  0.051  

300                  0.227

400                  0.113  

500                  0.090

600                  0.099

700                   0.165

800                   0.075

Now to find the mean, we have to use the below formula:

$Mean, \mu=\sum xP(x)$

              $=(100 \times 0.180)+(200 \times 0.051)+(300 \times 0.227)+(400 \times 0.113)+(500 \times 0.090)+(600 \times 0.099)+(700 \times 0.165)+(800 \times 0.075)$

              $=18+10.2+68.1+45.2+45+59.4+115.5+60$

              $=421.4$

Therefore, the mean is $\mu=421.4$