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3 years ago

Whats the step by step process to solve 3(×-9)=30

Mathematics

2 answers:

Sergio [31]3 years ago

7 0

step 1 : 3 • (x - 9) - 30 = 0 Step 2 :Step 3 :Pulling out like terms :

3.1 Pull out like factors :

3x - 57 = 3 • (x - 19)

Equation at the end of step 3 : 3 • (x - 19) = 0 Step 4 :Equations which are never true :

4.1 Solve : 3 = 0

This equation has no solution.
A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2 Solve : x-19 = 0

Add 19 to both sides of the equation :
 x = 19

One solution was found : x = 19

Murljashka [212]3 years ago

3 0

3(x-9)=30
3(x-9)+9=30+9
3x/3=39/3
x=39/3
x=13

You have to show a new line for each operation when the directions call for step by step.

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The back of jake's property is a creek. Jake would like to enclose a rectangular area, using the creek as one side and fencing f

kow [346]

Answer:

The maximum possible area of the pasture is 26,450 feet square.

Step-by-step explanation:

Let us assume the width of the rectangular area = m ft

and the length of the area = k ft

Also assume: ( one side with k units IS NOT FENCED)

So, the total perimeter of the fencing is:

2 m + k = 460

or, k = 460 - 2m ........ (1)

Now, AREA OF THE RECTANGULAR PORTION = Length x Width = k x m

Put k = 460 - 2m

We get: A = m (460 - 2m)

or, A = 460 m - 2m²

We need to find the maximum for the parabolic function A = 460 m - 2m²

The function has a maximum value as the quotient in front of x^2 is negative: -2 < 0

A (max) = $c-\frac{b^2}{4a}$ where a = -2, b = 460, c = 0

= $-\frac{(460)^2}{4(-2)} = 26,450$

A max = 26,450 sq ft.

The maximum possible area of the pasture is 26,450 feet square.

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4 years ago

) Choose ALL the numbers that are less than 6.58. 6.583 6.5 6.58 5.98 6.538 6.49

bonufazy [111]

Answer:

6.5, 6.49

Step-by-step explanation:

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3 years ago

The radius of a fully inflated soccer ball is 4.5 inches. After using the ball for a game, the match referee, Jason, measured th

forsale [732]

The volume of a sphere is:

V=(4pr^3)/3 so the initial volumes is:

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3 years ago

Cynthia Besch wants to buy a rug for a room that is 19 ft wide and 32 ft long. She wants to leave a uniform strip of floor aroun

Rainbow [258]

Answer:

The rug should be 15 ft wide and 28 ft long.

Step-by-step explanation:

I have attached a figure that represents the situation.

The the rug is $l$ by $h$ , the width of the strip of floor is $w$ .

We are told that Cynthia can only afford 420 square feet of carpeting; therefore, it must be that

$l*h=420$ (this says the area of the rug must be 420 square feet)

From the figure we see that

$l= 32-2w$

$h=19-2w$

Therefore,

$l*h=420\\\\(32-2w)(19-2w)=420$

We expand this equation and get:

$4w^2-102w+608=420\\\\4w^2-102w+188=0$

using the quadratic equation we get two solutions:

$w=2\\w=23.5$

since the second solution, namely $w=23.5$ , is larger than one of the dimensions of the room (is greater than 19 ft) it cannot be the width of the strip; therefore, we take $w=2$ to be our solution.

Now we find the dimensions of the rug:

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The rug is 15 ft wide and 28 ft long.

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4 years ago

Find the area A of triangle JKL with the vertices J(5,8), K(0,7), and L(5,4)

eimsori [14]

Answer:

Area of the triangle is 10 square units

Step-by-step explanation:

Recall that the formula for the area of a triangle is: "base x height / 2", and in this case, we can consider the triangle's base as the segment that joins the vertices (5, 4) and (5, 8) which gives a segment length of 4 units. The height of the triangle is then the distance between the third vertex (0,7) and the base, which is exactly 5 units. Then the area becomes:

Area = 4 x 5 / 2 = 10 square units.

5 0

3 years ago