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Liula [17]
3 years ago
5

|6x|+3=21 solve for X (absolute value)​

Mathematics
2 answers:
Fudgin [204]3 years ago
6 0

Answer:

x=3\text{ or } x=-3

Step-by-step explanation:

So we have the equation:

|6x|+3=21

First, subtract 3 from both sides:

|6x|=18

Definition of absolute value:

6x=18\text{ or } 6x=-18

Divide both sides by 6 for both equations:

x=3\text{ or } x=-3

And we're done!

Pavlova-9 [17]3 years ago
6 0

Answer:

x=3 and x=-3

Step-by-step explanation:

\left|6x\right|+3=21\\

Subtract 3 to both sides:

\left|6x\right|+3-3=21-3\\|6x|=18

Apply the absolute rule: If |a| = b and b > 0, a = -b or a = b.

Thus,

Case 1:

6x=18

Divide both sides by 6:

x=3

Case 2:

6x=-18

Divide both sides by 6:

x=-3

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For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant
nirvana33 [79]

Answer:

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of y with respect to x over the interval by definition of secant line:

r = \frac{y(b) -y(a)}{b-a} (1)

Where:

a, b - Lower and upper bounds of the interval.

y(a), y(b) - Function exaluated at lower and upper bounds of the interval.

If we know that y = 3\cdot x^{2}, a = 3 and b = 6, then the average rate of change of y with respect to x over the interval is:

r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}

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The average rate of change of y with respect to x over the interval [3,6] is 27.

b) The instantaneous rate of change can be determined by the following definition:

y' =  \lim_{h \to 0}\frac{y(x+h)-y(x)}{h} (2)

Where:

h - Change rate.

y(x), y(x+h) - Function evaluated at x and x+h.

If we know that x = 3 and y = 3\cdot x^{2}, then the instantaneous rate of change of y with respect to x is:

y' =  \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}

y' =  3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}

y' = 3\cdot  \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}

y' = 6\cdot  \lim_{h \to 0} x +3\cdot  \lim_{h \to 0} h

y' = 6\cdot x

y' = 6\cdot (3)

y' = 18

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

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