Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
1 answer:
Answer:
Step-by-step explanation
The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is
r = |p*-p|/|p|
we want r to be at most 10⁻³, thus
|p*-p|/|p| ≤ 10⁻³
|p*-p| ≤ |p|* 10⁻³
therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]
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Answer:
The net profit rate on the book is 5.41
Step-by-step explanation:
Given as :
The marks up percentage of book = m = 40%
The overhead rate is 16% of selling price
The cost price of book = c.p = $18.10
Let The profit = $p
Let The selling price = s.p
<u>Now, According to question</u>
mark up percentage =
I.e 40% =
Or, + 1 =
Or, =
Or, s. p =
∴ s.p = $25.34
So, selling price of book = s.p = $25.34
Now, The overhead percentage = 16%
i.e overhead rate =
Or, estimated cost = 16% × 25.34
I,e estimated cost = 0.16 × 25.34
∴ estimated cost = $4.05
Now,
Profit = selling price of book - estimated book cost
I.e p = $25.34 - $4.05
∴ p = $21.29
So, The profit rate% =
I.e The profit rate% =
∴ profit rate %= 5.41
So, The profit rate = p = 5.41
Hence, The net profit rate on the book is 5.41 Answer