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erica [24]
3 years ago
12

Round 56.834 to the nearest tenth

Mathematics
2 answers:
k0ka [10]3 years ago
8 0

Answer:

56.8

Step-by-step explanation:

8 is the tenth

numbers that are 4 or under stay the same

numbers that are 5 or above round up

EastWind [94]3 years ago
3 0

Answer:

56.8

Step-by-step explanation:

When rounding to the nearest tenth you look at the number behind the decimal. And the number in the hundredths place if it is 4 or lower you keep it the same. If it is 5-9 you up it by one.

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A falcon flies 800,000 meters in 4 hours. Use the formula d = rt, where d represents distance, r represents rate, and t represen
photoshop1234 [79]

Answer:

a. r=d/t b. 800000/4=200,000 c.800/2=200 d.not sure km are used more often as theyre simpler to use but there is not much that i am basing this off of

Step-by-step explanation:

5 0
4 years ago
What is 2+2x4x4 i need the answer fast.
Sergeeva-Olga [200]
Hey there 

Solutions 

1) First add 
2+2 = 4 

2) Multiply answer by 4 
4 x 4 = 16 

3) multiply answer by 4 
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Answer = 64 

Hope this helps 
6 0
3 years ago
Read 2 more answers
A professor has noticed that, even though attendance is not a component of the final grade for the class, students that attend r
andrew11 [14]

Answer:

A) 57%

B) 16%

C) 53%

D) 57%

Step-by-step explanation:

Let R1 be students that attend class regularly

R2 be students that don't attend class regularly

A be students that receives A's in class

A) From the question A/R1 =57%

P(A/R1) = 0.57

B) From the question students that receive As that does not attend lectures regularly =16%

C) P(R2) = 1 -0.57 = 0.43

P(A) = P(A/R1) × P(R1) + P(A/R2)×P(R2)

P(A) = (0.57× 0.81) + (0.16×0

43)

P(A) = 0.46 + 0.0688= 0.53

The overall percentage that recieved A's = 53%

D) 57% recieved A's given that they attend class regularly.

4 0
3 years ago
Which expression shows (3*100)+(5*10)+(5*1/10) in standard form?​
Ivenika [448]

Answer:

Step-by-step explanation: 3 x 100 + 4 x 10 + 5 x 1 Standard form is the reverse ...

7 0
3 years ago
Cancel the common factor of the numerator and the denominator and write specified expression
lisabon 2012 [21]

Step-by-step explanation:

<em>Hello</em><em>,</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>exists</em><em> </em><em>in</em><em> </em><em>numerator</em><em> </em><em>and</em><em> </em><em>denominator</em><em>,</em><em>right</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>Let's</em><em> </em><em>look</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em>, </em>

<em>here</em><em>,</em><em> </em><em>the</em><em> </em><em>expression</em><em> </em><em>is</em><em>, </em>

<em>=</em><em>4</em><em>(</em><em>x-2</em><em>)</em><em>/</em><em> </em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em><em>(</em><em>x-2</em><em>)</em>

<em>so</em><em>,</em><em> </em><em>here</em><em> </em><em>we</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>is</em><em> </em><em>(</em><em>x-2</em><em>)</em>

<em>now</em><em>,</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>it</em><em>.</em><em> </em><em>And</em><em> </em><em>after</em><em> </em><em>cancelling</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>=</em><em>4</em><em>/</em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em>

<em>Note</em><em>:</em><em>{</em><em> </em><em>we</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factors</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>multiply</em><em> </em><em>form</em><em>.</em><em>}</em>

<em><u>Hope it helps</u></em><em><u> </u></em>

3 0
3 years ago
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