1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
erica [24]
3 years ago
12

Round 56.834 to the nearest tenth

Mathematics
2 answers:
k0ka [10]3 years ago
8 0

Answer:

56.8

Step-by-step explanation:

8 is the tenth

numbers that are 4 or under stay the same

numbers that are 5 or above round up

EastWind [94]3 years ago
3 0

Answer:

56.8

Step-by-step explanation:

When rounding to the nearest tenth you look at the number behind the decimal. And the number in the hundredths place if it is 4 or lower you keep it the same. If it is 5-9 you up it by one.

You might be interested in
Find the odds in favor and the odds against a randomly selected person from Country X, age 25 and over, with the stated amount o
konstantin123 [22]

Answer:

25 : 63 and 63 : 25

Step-by-step explanation:

This is a complete question

The table shows the educational attainment of the population of Country X, ages 25 and over. Use the data in the table, expressed in millions, to solve the problem. of 10 questions ge 1: Ages 25 and Over, in Miltions 4 Years igh College 4 Years High School (Less than College School Only 4years) Cor Moce) Total Male 29 19 25 89 Female 11 28 23 Total 2 57 42 50 [176 Find the odds in favor and the odds against a randomty selected person from Country X.age 25 and over, with the stated amount of education. four years (or more) of college 21:67, 67:21 63:88, 88:63 25:63, 63:25 25:88, 88:25

According to the question, the relevant data provided in the question for the solution is as follows

Four years or more of college

Number of students = 50

Total = 176 students

Number of students does not belong = 126

So odds in favor is

= 50 : 126

= 25 : 63

And automatically out against the favor is 63 : 25

5 0
2 years ago
10÷250 and please no links​
Juli2301 [7.4K]

Answer:

10÷250

= 0.04

Step-by-step explanation:

that's the answers

4 0
2 years ago
Read 2 more answers
If Amelia would like to double her money in twelve years, how much interest does she need to earn? 6 percent 12 percent 10 perce
sveticcg [70]
We can assign the value "2x" as the amount of money that Amelia which to achieve in twelve years.
So, his initial money is X.
We can try each percent to test if it could double the amount in 12 years.
x+0.06*12years*x=1.72X
x+0.12*12*x=1.44x
x+0.1*12*x=2.2x
x+0.166*12*x=2.992x

Therefore, the answer is 10 percent.
4 0
3 years ago
Evaluate (ab)^2 for a=3 and b=4
grandymaker [24]

Answer:

144 is the answer


4 0
2 years ago
Read 2 more answers
100 POINTS!! MICROSOFT EXCEL
murzikaleks [220]

Step-by-step explanation:

A new coffee shop is being built. Its location is the reflection of the arcade's coordinates across

the y-axis. Which procedure will find the correct distance between the arcade and the new coffee shop

4 0
2 years ago
Read 2 more answers
Other questions:
  • Double-Angle and Half-Angle Identiies [See Attachment] Question 5
    5·1 answer
  • A pack of gum costs 75 cents. That is 3 cents less than three times what the pack cost 20 years ago. Which equation could be use
    7·1 answer
  • Prove that sin(Π÷14)sin(3Π÷14)sin(5Π÷14)=2​
    13·1 answer
  • What is the distance between (-6, 4) and (-8, 6) ​
    10·2 answers
  • If you quadratic equation has two complex roots and one of the roots is x+2i, what is the second root?
    7·1 answer
  • Find its square plzzzz
    10·1 answer
  • Find the height of a cylinder with a surface area of 1,206.4 in^2 and a radius of 8 in.
    10·2 answers
  • Is 120 divisible by 3 and 4
    15·2 answers
  • Find the value of |-4 + 3| · 8.
    7·2 answers
  • . If a landfill has a density of 1,200 pounds per cubic yard, what would be the volume required for 15- years worth of MSW to th
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!