The given operation involves just swapping the two rows, so carrying out 
on the matrix gives
![\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D5%265%265%5C%5C1%26-%5Cdfrac23%265%5Cend%7Barray%7D%5Cright%5D%5Cto%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26-%5Cdfrac23%265%5C%5C5%265%265%5Cend%7Barray%7D%5Cright%5D)
15 POINTS!! PLEASE HELP ASAP!!
1 answer:
Answer:
Total number of kilometers in the ride = 5 km
Number of kilometers Garret has already biked = k km
Number of kilometers Garret left to ride = 5 - k km
Number of minutes Garret takes per kilometer = 4 minutes.
Step-by-step explanation:
1. It takes 4 minutes for Garret to go a kilometer. Then
Number of minutes Garret takes per kilometer = 4 minutes.
2. Suppose the variable is the number of kilometers Garret has already biked.
3. Garret is partway through a 20-minute bike ride. It takes 4 minutes for him to go a kilometer. Then
Total number of kilometers in the ride is
4. Suppose the variable is the number of kilometers Garret has already biked. Then
km is the number of kilometers Garret left to ride.
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