The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>
The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
Read more on ratios;
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The law of cosines is
c= square root of a^2 + b^2 - 2ab cos c
the law of sines is
a = b(sin a /sin b)
x = 3.
Plug in 3 for x in the equation
14(3) + 64
Remember to follow PEMDAS. First, multiply 3 with 14
3 x 14 = 42
Finally, add 64
42 + 64 = 106
106 is your answer
hope this helps
term- 4x and 10
This is because to be a term it has to be + or -
Factor- 4x+10
This is because that is what is happening in the problem
Coefficient- 4y
I don't know what the constant would be, But I hope that this helps you
Hi it is 57 is a becase use a protractor