The answer would be 901 because they said what is the least number they would need to read and their goal is MORE than 900. The amount of books that they already had is useless information (Ignore). They love giving trick questions. :)
Answer:
Brownies made the most money
Step-by-step explanation:
Let c = cookies
b = brownies
We sold 51 items so c+b = 51
Cookies are .75 and brownies are 1.25
.75c + 1.25 b = 53.25
We have 2 equations and 2 unknowns
c = 51-b
Substituting into the second equation
.75(51-b) + 1.25b = 53.25
Distribute
38.25-.75b +1.25b = 53.25
Combine like terms
38.25+.5b = 53.25
Subtract 38.25 from each side
38.25 +.5b -38.25 = 53.25 -38.25
.5b =15
Divide each side by .5
.5b/.5 = 15/.5
b = 30
Now find c
c =51-b
c = 51-30
c = 21
They sold 30 brownies and 21 cookies
30 brownies * 1.25 =37.50
21 cookies *.75 = 15.75
Brownies made the most money
Answer:
f(x) = 2(x -3)² +5 or f(x) = 2x² -12x +23
Step-by-step explanation:
The equation of a quadratic is easily written in vertex form when the coordinates of the vertex are given. Here, the point one horizontal unit from the vertex is 2 vertical units higher, indicating the vertical scale factor is +2.
__
<h3>vertex form</h3>
The vertex form equation for a parabola is ...
f(x) = a(x -h)² +k . . . . . . vertex (h, k); vertical scale factor 'a'
<h3>equation</h3>
For vertex (h, k) = (3, 5) and vertical scale factor a=2, the vertex form equation of the parabola is ...
f(x) = 2(x -3)² +5 . . . . . vertex form equation
Expanded to standard form, this is ...
f(x) = 2(x² -6x +9) +5
f(x) = 2x² -12x +23 . . . . . standard form equation
The answer is 2 radical 3
<u>Given</u>:
Given that the graph OACE.
The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)
We need to determine the midpoint of EC.
<u>Midpoint of EC:</u>
The midpoint of EC can be determined using the formula,
Substituting the coordinates E(2t,0) and C(2p, 2r), we get;
Simplifying, we get;
Dividing, we get;
Thus, the midpoint of EC is (t + p, r)
Hence, Option A is the correct answer.