Question

Probability theory predicts that there is a 16.2% chance of a particular basketball player making 5 free throws in a row. If the basketball player taking 5 free throws is simulated 5000 times, in about how many of the simulations would you expect at least 1 missed free throw?

Answer 1

There is a 83.8% chance that the player will have at least 1 missed free throw.
5000 · 0.838 = 4190 simulations

Answer 2

Answer:

4190

Step-by-step explanation:

Given that,

Probability theory predicts that there is a 16.2% chance of a particular basketball player making 5 free throws in a row.

Let us assume that, A be the event that, 5 free throws happen. So

$P(A)=0.162$

So the probability of the event of not happening the event A or event of missing  at least 1 free throw will be,

$P(A^c)=1-0.162=0.838$

So, in 5000 trial, number of missed free throw will be,

$=0.838\times 5000=4190$