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adoni [48]
3 years ago
6

Simplify the following expression.

Mathematics
2 answers:
Mashcka [7]3 years ago
8 0
The answer is B.
I really hope this helps.
kipiarov [429]3 years ago
3 0
Hello,

The answer is B

Hope this helped :)
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Translate each English phrase in the following problem into an algebraic expression and set up the related equation. Let z be th
Ede4ka [16]

The English phrase of the obtained equation is 12 times z subtracted by 3. The obtained equation after solving is 12z -23

<h3>What exactly is simplification?</h3>

Simplifying means making something easier to do or comprehend, as well as making something less difficult.

Given data;

z be the unknown number

Given conditions;

1. The difference between a number and −23.

2.−23 is equal to the product of the number and 13.

The mathematical form of the given phrase is;

⇒ z - (-23) = z × 13

⇒z+23 = 13z

⇒12z -23

The English phrase of the obtained equation is 12 times z subtracted by 3.

Hence the simplification of the given expressions is 12z -23.

To learn more about the simplification, refer to:

brainly.com/question/23509407

#SPJ1

6 0
2 years ago
(b^4)^2 ???????????????
Bogdan [553]

Answer:

b^8

Step-by-step explanation:

3 0
3 years ago
Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
Read 2 more answers
PLZ HELP ME, I'M DOING A TEST I NEED HELP PLZ
Veronika [31]

Answer:

I think its c

Step-by-step explanation:

3 0
3 years ago
Need help due in 10 mins
Marina CMI [18]

Answer:

A) The amount of money deposited monthly

Step-by-step explanation:

y = 35x (slope) (amount deposited each month)+ 250 (y-intercept) (starting amount)

4 0
2 years ago
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