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frozen [14]
4 years ago
7

Write the fraction as a decimal and as a percent Fraction: 7/8

Mathematics
2 answers:
Dahasolnce [82]4 years ago
5 0

Answer:

7/8 = 0.875

7/8 = 87.5%

hope this helps, if so hit that thanks button please ;D

Basile [38]4 years ago
4 0

Fraction: 7/8

Decimal: 0.875

Percent: 87.5%

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Find the missing factor x^2-11x+18=(x-2)( )
tia_tia [17]
I'd use synthetic div. here, with 2 as my divisor:

      ________________
2   /   1    -11    18
                  2   -18
     ----------------------------
         1     -9      0

Note that the coefficients of the missing factor are given here and are 1 and -9.  Thus, (x-9) is the missing factor.
4 0
3 years ago
What is the answer (6√2)(-3√5)
alexgriva [62]

Solution:

- 18 \sqrt{10}

<h3>Step-by-step explanation:</h3>

<h3>1. Apply rule : a(-b) = -ab</h3>

<h3> </h3>

=  - 6 \sqrt{2}   \:  \: • \:  \: 3 \sqrt{5}

2. Apply radical rule : \sqrt{a}  \sqrt{b}  =  \sqrt{ab} , a \geqslant 0, b

=  6 \sqrt{2 \: • \: 5}  \: • \: 3

<h3>3.Multiply the numbers : 2 • 5 = 10</h3>

=6 \sqrt{10} •3

<h3>4.Multiply the numbers : - 6 • 3= - 18</h3>

=  - 18 \sqrt{10}

7 0
2 years ago
By coincidence, Norma's Obedience School trained the same number of dogs and cats last week. The school teaches dogs in groups o
IrinaK [193]
The answer is four or 4
3 0
2 years ago
Read 2 more answers
Question number 2 answer asap please<br><br><br>​
slava [35]

Answer:

The ordered pair that is the solution to the system lies in Quadrant IV

The x-coordinate of the solution is 9

The y-coordinate of the solution is -8

Step-by-step explanation:

8 0
3 years ago
If the gcd of 5 and 12 is 1 then
Art [367]

Answer:

The greatest common divisor (gcd) of two or more numbers referst to the largest positive integer that divides each of the integers. Also, two integers are said to be relatively prime, mutually prime, or coprime if the only positive integer that divides both of them is 1. Therefore, If the GCD of 5 and 12 is one, it means that the two numbers are mutually prime.

6 0
3 years ago
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