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3 years ago

What can be equal to 19

Mathematics

1 answer:

BartSMP [9]3 years ago

7 0

19 can be equal to 19 and it should turn out to be as a whole number which is 1

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rodeney is burning a music CD . The CD holds at most 90 minutes of music . Rodney has already selected 55 minutes of music . wri

lukranit [14]

55-90=35 theres your answer... its suspicious they give easy answers in middle school u sure thats the question?

4 0

3 years ago

What is 345.432 minus two hundredths ?

Alexandra [31]

Answer:

345.412

Step-by-step explanation:

8 0

3 years ago

Find the fourth roots of 16(cos 200° + i sin 200°).

NeTakaya

Answer:

See below.

Step-by-step explanation:

To find roots of an equation, we use this formula:

$z^{\frac{1}{n}}=r^{\frac{1}{n}}(cos(\frac{\theta}{n}+\frac{2k\pi}{n} )+\mathfrak{i}(sin(\frac{\theta}{n}+\frac{2k\pi}{n})),$ where k = 0, 1, 2, 3... (n = root; equal to n - 1; dependent on the amount of roots needed - 0 is included).

In this case, n = 4.

Therefore, we adjust the polar equation we are given and modify it to be solved for the roots.

Part 2: Solving for root #1

To solve for root #1, make k = 0 and substitute all values into the equation. On the second step, convert the measure in degrees to the measure in radians by multiplying the degrees measurement by $\frac{\pi}{180}$ and simplify.

$z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(0)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(0)\pi}{4}))$

$z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{\pi}{4}))$

$z^{\frac{1}{4}} = 2(sin(\frac{5\pi}{18}+\frac{\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{\pi}{4}))$

Root #1:

$\large\boxed{z^\frac{1}{4}=2(cos(\frac{19\pi}{36}))+\mathfrack{i}(sin(\frac{19\pi}{38}))}$

Part 3: Solving for root #2

To solve for root #2, follow the same simplifying steps above but change k to k = 1.

$z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(1)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(1)\pi}{4}))$

$z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{2\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{2\pi}{4}))\\$

$z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{\pi}{2}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{\pi}{2}))\\$

Root #2:

$\large\boxed{z^{\frac{1}{4}}=2(cos(\frac{7\pi}{9}))+\mathfrak{i}(sin(\frac{7\pi}{9}))}$

Part 4: Solving for root #3

To solve for root #3, follow the same simplifying steps above but change k to k = 2.

$z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(2)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(2)\pi}{4}))$

$z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{4\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{4\pi}{4}))\\$

$z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\pi))+\mathfrak{i}(sin(\frac{5\pi}{18}+\pi))\\$

Root #3:

$\large\boxed{z^{\frac{1}{4}}=2(cos(\frac{23\pi}{18}))+\mathfrak{i}(sin(\frac{23\pi}{18}))}$

Part 4: Solving for root #4

To solve for root #4, follow the same simplifying steps above but change k to k = 3.

$z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(3)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(3)\pi}{4}))$

$z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{6\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{6\pi}{4}))\\$

$z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{3\pi}{2}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{3\pi}{2}))\\$

Root #4:

$\large\boxed{z^{\frac{1}{4}}=2(cos(\frac{16\pi}{9}))+\mathfrak{i}(sin(\frac{16\pi}{19}))}$

The fourth roots of 16(cos 200° + i(sin 200°) are listed above.

3 0

3 years ago

Question below answer correctly please

ratelena [41]

Answer:

C: x≥12

D: x<-15

E: x<7.5 or 15/2

F: x<-8

G: x≥-2.7 or -8/3

H: x≥-6

Step-by-step explanation:

I trust you know how to graph it

3 0

2 years ago

How many acute, obtuse, and right angles are in this figure?

Tanya [424]

Hey!

I hope you don't mind, but before I answer this question I'd like to do a quick review of some general angles and how to tell which is which.

QUICK REVIEW

So, let's first review what an acute angle is. An acute angle is an angle that is smaller than 90°. The word acute basically means having a sharp or pointy end. So this is a helpful way to remember what an acute angle is.

Now, let's review what an obtuse angle is. An obtuse angle is an angle that is more than 90°. If an angle measures over 90° that it is more than likely that it is an obtuse angle.

Last but not least a right angle. A right angle is an angle that has to be exactly 90°. If an angle is 90° than it is most definitely a right

END QUICK REVIEW

Let's start by finding out the angle in the top left hand corner. The angle is clearly no more that 90° and is not 90° exactly. This angle must be an acute angle. We can also tell that it is an acute angle because the angle is sharp.

Now let's look at the angle on the bottom left hand corner. The angle is clearly no less than 90° and more than 90° exactly. This angle must be an obtuse angle.

Since the angles are basically the same on the other side, we won't be reviewing those. Now we'll count all the angles we have.

Acute Angles - 2

Obtuse Angles - 2

Right Angles - 0

So, this means that in the figure shown above, there are 2 acute angles, 2 obtuse angles, and no right angles.

Hope this helps!

- Lindsey Frazier ♥

4 0

3 years ago