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IRISSAK [1]
4 years ago
15

What is the greatest common factor of 20x^4 and 6x^3 X^3 X^4 2x^3 2x^4

Mathematics
2 answers:
slega [8]4 years ago
8 0
20x^4 and 6x^3 would be " 2x^3 "
Lesechka [4]4 years ago
3 0
The GCF of 20x^4 and 6x^3 would be " 2x^3 " 
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a recipe calls for 12 ounces of raisin. raisins come in boxes of 170 g. how many boxes of raisins are needed for the recipe?
Olin [163]

Hi there! Hope this helps, and if it does, please mark brainliest!

Answer:

2 boxes

Step-by-step explanation:

There are roughly 28 grams in an ounce. So if you have 12 ounces, times 28 by 12, which is 336, so you need 336 grams of raisins. Divide by 170, the number of grams in one box, which would be 1.98 boxes, but you have to round up, so you would need two boxes.

5 0
3 years ago
A restaurant chain ordered 3,945 pounds of rice in 20-pound bags.About how many 20-pound bags of rice did the chain order
Zanzabum

Answer:

Approximately 197 bags.HOPE THIS HELPS

Step-by-step explanation:divided 3945 by 20 which gave me 197.25  and rounded


7 0
4 years ago
Read 2 more answers
Multiply the complex numbers.<br><br> (5+1i)(-3+2i)
Mumz [18]

Answer:

-17+7i

Step-by-step explanation:

5 0
4 years ago
A motorcyclist traveling at 30.7 km/h accelerates after passing a sign post marking the city limits. If it takes 4.9 seconds for
MissTica

Remark

Writing down the givens for these questions is almost a command. You must know which equation of the big 4 to use. The givens + what you want to find will determine the equation.

Givens

vi = 30.7 km/hr = 30.7 km/hr *[1000m/1km]*[1hr/3600sec] = 8.52m/sec

vf = 120 km/hr = 120 km/hr * [1000 m/1 km]*[1h/3600 sec] = 33.3 m/s

t = 4.9 seconds

d = ???

Formula

d = (vi + vf)*t/2

Solve

d = ( 33.3+8.52 )*4.9/2

d = (41.85333)*4.9/2

d = 205.02/2

d = 102.51 m<<<Answer


8 0
3 years ago
Read 2 more answers
Please help, picture attached.
REY [17]

It is a step function. The question is from a practice test right?

3 0
3 years ago
Read 2 more answers
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