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dezoksy [38]
3 years ago
5

DEFG is an isosceles trapezoid. Find the measure of E.

Mathematics
2 answers:
abruzzese [7]3 years ago
4 0
If it is isosceles angle E must be equal to F, in this case 75°
Scilla [17]3 years ago
4 0

Answer:  The measure of ∠E is 75°.

Step-by-step explanation: Given that DEFG is an isosceles trapezoid, where m∠D = 105° and m∠F = 75°.

We are to find the measure of ∠E.

ISOSCELES TRAPEZOID is a trapezoid in which the base angles are equal and so the left and right side lengths are also equal.

Therefore, in the isosceles trapezoid DEFG, we have

m∠D = m∠G,  m∠E = m∠F  and  DE = FG.

Since, m∠D = 105°, so m∠G =  105°.

The sum of all the four angles of a quadrilateral is 360° and a trapezoid is a quadrilateral with a set of opposite parallel sides, so in the trapezoid DEFG, we have

m\angle D+m\angle E+m\angle F+m\ange G=360^\circ\\\\\Rightarrow 105^\circ+m\angle E+75^\circ+105^\circ=360^\circ\\\\\Rightarrow m\angle E+285^\circ=360^\circ\\\\\Rightarrow m\angle E=360^\circ-285^\circ\\\\\Rightarrow m\angle E=75^\circ.

Thus, the measure of ∠E is 75°.

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Black_prince [1.1K]
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2 years ago
What is the equation of the quadratic graph with a focus of (1, 1) and a directrix of y = −1? PLs HELP!!
Delicious77 [7]
ANSWER
f(x)= \frac{1}{4} {(x - 1)}^{2}

EXPLANATION

Since the directrix is
y = - 1

the axis of symmetry of the parabola is parallel to the y-axis.

Again, the focus being,

(1,1)

also means that the parabola will open upwards.

The equation of parabola with such properties is given by,

{(x - h)}^{2} = 4p(y - k)
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(h,k)

is the vertex of the parabola.

The directrix and the axis of symmetry of the parabola will intersect at
(1, - 1)

The vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix.

This implies that,
h = \frac{1 + 1}{2} = 1

and
k = \frac{ - 1 + 1}{2} = 0

The equation of the parabola now becomes,

(x - 1) ^{2} = 4p(y - 0)

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This means that,

p = - 1 \: or \: 1

Since the parabola opens up, we choose
p = 1
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{(x - 1)}^{2} = 4(1)(y - 0)

This simplifies to
{(x - 1)}^{2} = 4y

or

y = \frac{1}{4} {(x - 1)}^{2}

This is the same as,

f(x)= \frac{1}{4} {(x - 1)}^{2}

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