Answer:
D
Step-by-step explanation:
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Answer:
-8
Step-by-step explanation:
what do you think, when you look at the examples given in the problem definition ?
don't you see the pattern, that f(x) = x+2 ?
f(1) = 1+2 = 3
f(2) = 2+2 = 4
f(3) = 3+2 = 5
so, if we follow this assumption, then
f(-10) = -10 + 2 = -8
I am not so sure of this but I feel it would serve as hint
It’ll be C or B with no soul took by finding the value.
13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0
Recall the double angle identity,
sin^2(x) = (1 - cos(2x))/2
If we let x = 13pi/12, then
sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]
where we took the negative square root because we expect a negative value.
Now, because cosine has a period of 2pi, we have
cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2
Then
sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]
sin(13pi/12) = - sqrt[2 - sqrt[3]]/2
