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tino4ka555 [31]
3 years ago
11

Calculate the ratio of surface area to volume of an imaginary cubic cell measuring 4mm long on each side

Mathematics
2 answers:
alexira [117]3 years ago
7 0

Answer:

3/2

Step-by-step explanation:

surface area = (2×base) +( height×base perimeter )

                     = (2×(4×4)) +( 4×(4×4) )

                     = 32 + 64

                     = 96 mm

volume = side³

             = 4³

             = 64 mm

the ratio of surface area to volume = 96/64 = 3/2

Mkey [24]3 years ago
5 0

Step-by-step explanation:

Surface area of cubic cell

= 6(side)^{2}  \\  = 6 \times  {4}^{2}  \\  = 6 \times 16 \\  = 96 \:  {mm}^{2}  \\  \\ volume \: of \:cubic \: cell  \\ =  {(side)}^{3}  \\  =  {4}^{3}  \\  = 64 \:  {mm}^{3} \\

Ratio of surface area to volume of imaginary cubic cell

= \frac{96}{64}\\ = \frac{3}{2}\\=3 : 2

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Find the missing angle.<br> Enter the number that belongs in the green box.<br> Enter
Ivenika [448]

Answer:

35 degrees

Step-by-step explanation:

The sum of all angles in a triangle equals to 180

To find angle z, just subtract 55 and 90 from 180

180-55-90= 35

Angle z = 35 degrees

Hope this helps

8 0
2 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
3 years ago
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Yakvenalex [24]
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Crazy boy [7]

Answer:ndbdnd ndbdnd 192

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3 years ago
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mafiozo [28]
A= (2,1)
B=(1,2)
C=(3,2)
3 0
3 years ago
Read 2 more answers
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