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Maru [420]
4 years ago
12

Evaluate f(3) for the piecewise function: f(x) = Which value represents f(3)? –11 8 12.5 16

Mathematics
2 answers:
Nonamiya [84]4 years ago
9 0
Hello!

-3x-2=-3(3)-2=-9-2= -11
Therefore, The Correct Answer would be 100%:

"-11", Option "A".

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)
Misha Larkins [42]4 years ago
9 0

Answer:

-3x-2=-3(3)-2=-9-2= -11

Therefore, The Correct Answer would be 100%:

"-11", Option "A".

Step-by-step explanation:

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Solve the inequality 2x – 5 > 7
ziro4ka [17]
<span>2x – 5 > 7 
Add 5 to both sides
2x > 12
Divide 2 on both sides
Final Answer: x > 6</span>
7 0
3 years ago
A certain slot machine has three identical independent wheels, each with 13 symbols as follows: 1 bar, 2 lemons, 2 bells, 2 plum
kari74 [83]

Answer:

Step-by-step explanation:

Given

there are 13 symbols in slot machines i.e. 1 bar , 2 lemons , 2 bells ,2 plums ,3 cherries , 3 oranges

there are Total of 3 machines

Probability of getting bar in machine is \frac{1}{13}

Probability of getting 3 bar on 3 machine=\frac{1}{13} \times\frac{1}{13}\times \frac{1}{13}=\frac{1}{2197}=0.0004

Probability of getting an orange=\frac{3}{13}

Probability of getting 3 oranges  on 3 machine=\frac{3}{13} \times\frac{3}{13}\times \frac{3}{13}=\frac{27}{2197}=0.0122

Probability of getting a Plum=\frac{2}{13}

Probability of getting 3 Plums  on 3 machine=\frac{2}{13} \times\frac{2}{13}\times \frac{2}{13}=\frac{8}{2197}=0.0036

5 0
3 years ago
Two boats left a base camp at bearing of S60°E and S50°W at speeds of 50km/h and 70km/h respectively. Find the distance between
ivolga24 [154]

Answer:

  • 197.93 km

Step-by-step explanation:

Let the base camp is point A and boats' locations after two hours are points B and C.

By connecting the three points together we get a triangle ABC with sides:

  • AB = 50*2 = 100 km
  • AC = 70*2 = 140 km

The angle between AB and AC is:

  • 60 + 50 = 110 degrees (opposite directions from south)

We are looking for the distance BC, which can be found by using the law of cosines:

  • BC² = AB² + AC² - 2AB*AC*cos ∠BAC
  • BC² = 100² + 140² - 2*100*140*cos 110°
  • BC²  = 39176.56 (rounded)
  • BC = √39176.56 = 197.93 km (rounded)

The distance between the boats is 197.93 km.

7 0
2 years ago
Max is paid a salary of $225 a week plus %2.5 commission on his total sales. What was max's total sales for the week if he made
torisob [31]
So we know he made 4,650 of sales and we need 2.5% of that

First to find 2.5% of 4650 we could do 

x/4650 = 2.5/100 
 Cross multiply to get

100x = 11625
x = 116.25

So his salary for this week would be 225 + 116.25 = 341.25
8 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
4 years ago
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