Let's solve your equation step-by-step.
3−6(x−7)=42−6x
Step 1: Simplify both sides of the equation.
3−6(x−7)=42−6x
3+(−6)(x)+(−6)(−7)=42+−6x(Distribute)
3+−6x+42=42+−6x
(−6x)+(3+42)=−6x+42(Combine Like Terms)
−6x+45=−6x+42
−6x+45=−6x+42
Step 2: Add 6x to both sides.
−6x+45+6x=−6x+42+6x
45=42
Step 3: Subtract 45 from both sides.
45−45=42−45
0=−3
Therefore, this is No Solutions.
We want double sixes. This means that we want both the first roll and the second roll to be 6.
The given point is given as (r1 , r2) where:
r1 is output from first roll
r2 is output from second roll
Since we want both outputs to be 6, therefore, the answer would be: (6,6)
4/3th a 100th per distance of both.
<span>Susanne is 16 years old.</span>
b = Bob's age
s = Susanne's age
d = Dakota's age
Bob's age is 4 times greater than Susanne's age:
b = 4s
Dakota is three years younger than Susanne:
d = s - 3
The sum of Bob's, Susanne's, and Dakota's ages is 93:
b + s + d = 93
solve these equations:
b = 4s
d = s - 3
b + s + d = 93
and get:
b = 64 years
s = 16 years
(remember that s = Susanne)
d = 13 years